Answer: 
Explanation:
According to ideal gas equation:
P = pressure of gas = 0.987 atm
V = Volume of gas = 12 L
n = number of moles = 0.50
R = gas constant =
T =temperature = ?
Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is
Answer:
[H⁺] = 5.012 x 10⁻⁹. & [OH⁻] = 1.995 x 10⁻⁶.
Explanation:
∵ pH = - log[H⁺]
8.3 = - log[H⁺]
∴ log[H⁺] = - 8.3.
<em>∴ [H⁺] = 5.012 x 10⁻⁹.</em>
∵ [H⁺][OH⁻] = 10⁻¹⁴.
<em>∴ [OH⁻] = 10⁻¹⁴/[H⁺] </em>= 10⁻¹⁴/(5.012 x 10⁻⁹) = <em>1.995 x 10⁻⁶.</em>
Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.
