Answer:
Common (industrial) uses for cadmium today are in batteries, alloys, coatings (electroplating), solar cells, plastic stabilizers, and pigments
Answer - Pure water
Reasoning - Can be stirred into the water to form homogeneous :).
Answer:
Earnings based on how much they sell
Explanation:
A sales presentation can be defined as series of talk given by a salesperson with the attempt to persuade someone or a potential customer to buy a particular product, by giving information it. Some salespersons resort to the use of dramatics so as to initiate and close the sale of a particular product by engaging in series of theatrical actions.
In sales and marketing, the term closing with respect to a sales can be defined as the process of making a business sale successful such as through the exchange of money for a particular product or goods.
For a salesperson to be able to close a sales, he or she require abilities such as courage, negotiation skills, listening ears and interpersonal skills to do so or achieve a successful sales. After a successful sales, they're entitled to a percentage of the amount made from selling a particular product or closing a deal based on what is stated in the contract. These amount of money earned with respect to each sales is generally referred to as commissions.
Commission can be defined as an amount of money earned based on how much a salesperson sell.
Answer:
The volume of nitrogen oxide formed is 35.6L
Explanation:
The reaction of nitric acid with copper is:
Cu(s) + 4HNO₃ → Cu(NO₃)₂ + 2NO₂(g) + 2H₂O(l)
Moles of copper are:
![4.95cm^3\frac{8.95g}{1cm^3} \frac{1mol}{63.55g} = 0.697 moles](https://tex.z-dn.net/?f=4.95cm%5E3%5Cfrac%7B8.95g%7D%7B1cm%5E3%7D%20%5Cfrac%7B1mol%7D%7B63.55g%7D%20%3D%200.697%20moles)
Moles of nitric acid are:
![230mL\frac{1.42g}{mL} \frac{68g}{100g} \frac{1mol}{63.01g}=3.52moles](https://tex.z-dn.net/?f=230mL%5Cfrac%7B1.42g%7D%7BmL%7D%20%5Cfrac%7B68g%7D%7B100g%7D%20%5Cfrac%7B1mol%7D%7B63.01g%7D%3D3.52moles)
As 1 mol of Cu reacts with 4 moles of HNO₃:
0.697 mol Cu × (4mol HNO₃ / 1mol Cu) = 2.79 moles of HNO₃ will react. That means Cu is limiting reactant.
Moles of NO₂ produced are:
0.697 mol Cu × (2mol NO₂ / 1mol Cu) = <em>1.394 moles of NO₂</em>
Using PV = nRT
<em>Where P is pressure (735torr / 760 = 0.967atm); n are moles (1.394mol); R is gas constant (0.082atmL/molK); T is temperature (28.2°C + 273.15 = 301.35K). </em>
Thus, volume is:
V = nRT / P
V = 1.394mol×0.082atmL/molK×301.35K / 0.967atm
V = 35.6L
<em>The volume of nitrogen oxide formed is 35.6L</em>