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stich3 [128]
3 years ago
14

Ammonia (NH3) burns in air to form nitrogen dioxide and water. Calculate grams of nitrogen dioxide produced if 4.0 grams of ammo

nia are consumed
Chemistry
1 answer:
kenny6666 [7]3 years ago
8 0
The balanced equation for the above reaction is;
4NH₃ + 7O₂  --> 4NO₂  + 6H₂O
stoichiometry of NH₃ to NO₂ is 4:4
the number of NH₃ moles consumed are - 4.0 g / 17 g/mol = 0.24 mol
number of NH₃ moles reacted are equivalent to number of NO₂ moles formed 
therefore number of NO₂ moles formed - 0.24 mol x 46 g/mol = 11.04 g
mass of NO₂ formed is 11.04 g
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What is the weight of a 90kg man standing on the moon, where gmoon = 1.64 m/s2?
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Answer:

The weigth of a 90kg man standing on the moon is <u><em>147.6 N (option C)</em></u>

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The formula that allows you to calculate the weight of any body is:

W = m*g

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In this case,  the mass m has a value of 90 kg and the gravity g has a value of 1.64 m/s², which is the value of the acceleration of gravity of the moon. Then:

W=90 kg* 1.64 m/s²

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Finally, <u><em>the weigth of a 90kg man standing on the moon is 147.6 N (option C)</em></u>

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