The balanced equation for the above reaction is; 4NH₃ + 7O₂ --> 4NO₂ + 6H₂O stoichiometry of NH₃ to NO₂ is 4:4 the number of NH₃ moles consumed are - 4.0 g / 17 g/mol = 0.24 mol number of NH₃ moles reacted are equivalent to number of NO₂ moles formed therefore number of NO₂ moles formed - 0.24 mol x 46 g/mol = 11.04 g mass of NO₂ formed is 11.04 g
