Answer:
D. Acidic salt
Explanation:
Acidic salts:
Salts formed by incomplete neutralisation of poly-basic acids are called acidic salts. Such salts still contain one or more replaceable hydrogen atoms. These salts when neutralised by bases form normal salts.
Answer:
I don't know and I don't understand
Explanation:
I don't know and I don't understand
sorry
sorry for not being able to answer your question
Molar mass is the mass of one stable molecule of a compound, that cannot join with another molecule of the same kind to form a new one, while an empirical formula is the molecular formula in its simplest form. E.g. empirical formula of ethene is CH2while its molecular formula is C2H4.
Change occurs in the density of the gummy bear to change if we soaked it in isopropanol.
<h3>Effects on density by soaking isopropanol</h3>
We expect the density of the gummy bear to change if we soaked it in isopropanol because the gummy bear absorb the liquid which increase its density due to increasing weight of the gummy bear.
If a substance gains weight then its density also increases and we know that when the gummy bear was soaked in the isopropanol then its weight increases so its density is also changes so we can conclude that change occurs in the density of the gummy bear to change if we soaked it in isopropanol.
Learn more about density here: brainly.com/question/1354972
Answer:
k ≈ 9,56x10³ s⁻¹
Explanation:
It is possible to solve this question using Arrhenius formula:
![ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%20%5Cfrac%7B-Ea%7D%7BR%7D%20%28%5Cfrac%7B1%7D%7BT2%7D%20-%5Cfrac%7B1%7D%7BT1%7D%20%29)
Where:
k1: 1,35x10² s⁻¹
T1: 25,0°C + 273,15 = 298,15K
Ea = 55,5 kJ/mol
R = 8,314472x10⁻³ kJ/molK
k2 : ???
T2: 95,0°C+ 273,15K = 368,15K
Solving:
![ln\frac{k2}{k1} = 4,257](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%204%2C257)
![\frac{k2}{k1} = 70,593](https://tex.z-dn.net/?f=%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%2070%2C593)
![{k2} = 9,53x10^3 s^{-1}](https://tex.z-dn.net/?f=%7Bk2%7D%20%3D%209%2C53x10%5E3%20s%5E%7B-1%7D)
<em>k ≈ 9,56x10³ s⁻¹</em>
I hope it helps!