Question

How many moles of NaCl are present in 2.50 L of a 0.070 M solution?

Answer 1

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

$M = \dfrac{n}{V(in\ L)}$

So,

$n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles$

Therefore, number of moles of NaCl is 0.175 moles.