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d1i1m1o1n [39]
3 years ago
5

How many moles of NaCl are present in 2.50 L of a 0.070 M solution?

Chemistry
1 answer:
posledela3 years ago
6 0

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

M = \dfrac{n}{V(in\ L)}

So,

n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles

Therefore, number of moles of NaCl is 0.175 moles.

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