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3 years ago

Ameadow food chain is shown.

Chemistry

2 answers:

GalinKa [24]3 years ago

7 0

The mouse is a Secondary consumer

Flauer [41]3 years ago

4 0

Answer:

the mouse is the secondary consumer

Explanation:

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Another name for a renewable energy source

Ira Lisetskai [31]

Answer:

Solar Power, HEP (Hydroelectric Power), Wind Power, etc...

Explanation:

These are some common examples of renewable energy source.

7 0

3 years ago

How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)

Svetllana [295]

Answer:

$atoms= 1.204x10^{24}atoms$

Explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

$atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms$

Best regards!

4 0

2 years ago

Suppose you mix one mole of sulfuric acid (H2SO4) with 1 mole of sodium hydroxide(NaOH).

olasank [31]

Answer & Explanation:

The neutralization of H₂SO₄ with NaOH is occurred according to the balanced equation:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O,

It is clear that every 1.0 mol of H₂SO₄ needs 2 mol of NaOH to be neutralized completely.

So, when you mix one mole of sulfuric acid with 1 mole of sodium hydroxide, there will be an excess of sulfuric acid.

Thus, the pH of the solution remain below 7.

7 0

3 years ago

Where do you place the symbols that represent the state of matter in an equation?

nexus9112 [7]

Subscript in a pair of brackets

5 0

3 years ago

A 40.2 g sample of a metal heated to 99.3Â°C is placed into a calorimeter containing 120 g of water at 21.8Â°C. The final temper

aliina [53]

Answer:

B) Iron (c=0.45 J/g°C)

Explanation:

Given that:-

Heat gain by water = Heat lost by metal

Thus,

$m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

$m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)$

For water:

Mass = 120 g

Initial temperature = 21.8 °C

Final temperature = 24.5 °C

Specific heat of water = 4.184 J/g°C

For metal:

Mass = 40.2 g

Initial temperature = 99.3 °C

Final temperature = 24.5 °C

Specific heat of metal = ?

So,

$120\times 4.184\times (24.5-21.8)=40.2\times C_{metal}\times (99.3-24.5)$

$40.2C_{metal}\left(99.3-24.5\right)=120\times \:2.7\times \:4.184$

$40.2C_{metal}\left(99.3-24.5\right)=1355.616$

$C_{metal}=0.45\ J/g^0C$

This value corresponds to iron. Thus answer is B.

3 0

3 years ago