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Lerok [7]
3 years ago
5

Ameadow food chain is shown.

Chemistry
2 answers:
GalinKa [24]3 years ago
7 0
The mouse is a Secondary consumer
Flauer [41]3 years ago
4 0

Answer:

the mouse is the secondary consumer

Explanation:

You might be interested in
Which particle has a negative charge?
sweet [91]

Answer: A

Explanation: Beta particles have a charge of -1

6 0
3 years ago
Read 2 more answers
Which conversion factor correctly shows the relationship between moles and representative particles?
strojnjashka [21]
This is given by Avogagro number: 1 mol = 6.02*10^23 particles

Then you can do whichever to these two relations, because they are equivalent:

- 1mol / 6.02*10^23 representative particles, and
- 6.02*10^23 representative particle /1 mol

Only the second option of the question includes one of the valid conversion factors. Then, the conversion factor of the second option is the right answer
8 0
3 years ago
How many moles of O2 are needed to react with 2.35 mol of C2H2?
Mrrafil [7]
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2

x =  \frac{2.35 \times 5}{2}  = 5.875 \: mol
answer: 5.875 mol
5 0
3 years ago
Read 2 more answers
What are three units you can measure moler mass in
liraira [26]

By looking at a periodic table, we can conclude that the molar mass of lithium is 6.94g, the molar mass of zinc is 65.38g, and the molar mass of gold is 196.97g. Each of these quantities contains 6.02×1023 atoms of that particular element. The units for molar mass are grams per mole, or g/mol.

So The answers are Lithium, Gold, Zinc

Hope This Helps

~Zero~

3 0
2 years ago
Read 2 more answers
A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilib
DochEvi [55]

Answer:

[IBr] = 0.049 M.

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

I_2+Br_2\rightarrow 2IBr

It is possible to set up the following equilibrium expression:

K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110

Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of x (reaction extent) would be:

0.0110=\frac{(2x)^2}{(0.50-x)^2}

Which can be solved for x to obtain two possible results:

x_1=-0.0277M\\\\x_2=0.0245M

Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:

[IBr]=2x=2*0.0249M=0.049M

Regards!

7 0
2 years ago
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