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➷ 4 x 2 = 8
4 x 1 = 4
4 x 4 = 16
16 + 8 + 4 = 28
The answer is option D. 28
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I’m pretty sure it will be the answer choice B
The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:
no. of moles= mass/ RFM
= 0.745/78
=0.00955moles
Therefore the 0.00955 moles should be in the 35.18 ml
therefore 1000ml of the solution will have:
(0.00955ml×1000ml)/35.18
=0.2715moles
The solution will be 0.27M hydrochloric acid
Answer:
3.38 moles of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4CH2OH + 5O2 → 4CO2 + 6H2O
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Finally, we shall determine the number of mole of O2 needed to react with 2.7 moles of CH2OH. This can be obtained as follow:
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Therefore, 2.7 moles of CH2OH will require = (2.7 × 5)/4 = 3.38 moles of O2 for complete combustion.
Thus, 3.38 moles of O2 is required.
The atomic number increases moving left to right across a period and subsequently so does the effective nuclear charge. Therefore, moving left to right across a period the nucleus has a greater pull on the outer electrons and the atomic radii decreases.
