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julsineya [31]
3 years ago
14

What is the molarity of a solution that contains 4.3 mol of acetic acid (C2H3O2) in 450. mL of solution?

Chemistry
1 answer:
lord [1]3 years ago
3 0

Hey there !


Number of moles of solution: 4.3 moles

Volume in liters:

450.0 mL / 1000 => 0.45 L

Therefore:

Molarity = number of moles / volume of solution ( L)

Molarity = 4.3 / 0.45

=> 9.55 M

Hope that helps!

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Molecular weight of PbCl2 = 278 g/mole Mass of beaker + PbCl2 = 62.19 g Mass of beaker = 57.77 g Mass of PbCl2 per 100 mL = g Mo
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PbCl2--->Pb2+  +  2Cl-

The  mass   of  PbCl2   is   =mass   of  the  beaker+Pbcl2  minus   mass  of  the  beaker
that  is  62.19-57.77g=  4.42grams

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concentration  of  (Pb2+)
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7 0
3 years ago
Sodium carbonate can be prepared by heating sodium bicarbonate. 2 NaHCO3(s) ----&gt; Na2CO3(s) + CO2(g) + H2O(g). Given that DHo
Likurg_2 [28]

Answer:

T = 401.6 K

Explanation:

Given reaction:

NaHCO3(s) ----> Na2CO3(s) + CO2(g) + H2O(g)

The thermodynamic parameters; ΔG°, ΔH° and ΔS° are related via the Gibbs -Helmholtz equation given as:

\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}----(1)

For a given reaction, the gibbs free energy change ΔG° is related to the equilibrium constant K as:

\Delta G^{0}=-RTln(K) ---(2)

It is given that K = 1,

Therefore,

\Delta G^{0}=-RTln(1) = 0

Substituting for ΔG° in equation (1)

0=\Delta H^{0}-T\Delta S^{0}

\Delta H = T\Delta S

T = \Delta H^{0}/\Delta S^{0}=\frac{128.9 kJ}{0.321 kj/mol-K}=401.6 K

5 0
3 years ago
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