Answer:
True
Explanation:
There are many formatting options from color, size, and many more.
Hope this helps!
Answer:
Following are the algorithm to this question:
y = 0 // initialize variable y that assigns the value 0
p = 1 // initialize value 1 in the variable p which also known as starting position
init num = 1//define variable num that assign value 1
for j = 1 to n: //defining loop
y = m[j] - m[p]
if (y > 10) //defining if block
num++; //increment num variable
p=i; //holding loop value in p variable
y= 0//assign value 0 in y variable
Explanation:
Following are the runtime analysis of the above-given algorithm:
The above-provided algorithm is greedy, but if it doesn't exceed the scope, it operates by greedily choosing its next object. Therefore the algorithm selects the fewest number of pens.
Running time:
This algorithm merely iterates once over all the points. The run-time is therefore O(n).
Answer:
Runa, because she’s like me I r l lol
Explanation:
Answer: A loop will continue running until the defined condition returns false . ... You can type js for , js while or js do while to get more info on any of these. ... initialization - Run before the first execution on the loop. ... But it can be used to decrement a counter too. statement - Code to be repeated in the loop.
Explanation:
Answer:
atof
Explanation:
atof function is used to convert a string to a double.
It takes a single parameter of type const char * and returns a double value.
The function signature is: double atof (const char* str);
In order to use this function in the code, you need to include the header file <stdlib.h>
For example:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char str[5] = "0.01";
double d = atof(str);
printf("Value = %f\n", d);
return 0;
}
