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tatyana61 [14]
3 years ago
5

Which set of numbers best describes the possible values of x in the equation below?[x-1]=[x] all integer values of x all real nu

mber values of x only negative values of x only fractional values of x
Mathematics
2 answers:
natima [27]3 years ago
6 0

<u>Answer Choices:</u>

A) all integer values of x

B) all real number values of x

C) only negative values of x

D) only fractional values of x

<u>Answer:</u>

D

This is the correct answer on E2020.

SCORPION-xisa [38]3 years ago
3 0

[x] represents floor function also called as Greatest integer function.

Floor function is the function that takes as input a real number and gives as output the greatest integer less than or equal to.

like [1.5]=1

[0.7]=0

[-0.3]=-1

Now we have to find set of x-values which satisfies equation [x-1]=[x]

Due to -1 in [x-1], it always produces output value one less than value of [x]

for example when x=0.5 then [x]=[0.5]=0, [x-1]=[0.5-1]=[-0.5]=-1

when x=1.5 then [x]=[1.5]=1, [x-1]=[1.5-1]=[0.5]=0

when x=3 then [x]=[3]=3, [x-1]=[3-1]=[2]=2

From above results we can see that there is no value of x which satisfies the given equation [x-1]=[x]

Hence there is NO solution.

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6 0
2 years ago
How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not
Jet001 [13]

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

\dbinom52=\dfrac{5!}{2!(5-2)!}=10

ways of picking the vowels, and

\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

4!\dbinom52\dbinom{20}2=\boxed{45,600}

Keep in mind that this means words like TRIES and TIRES are treated as different.

8 0
2 years ago
The data in this table represents a linear function.
Leviafan [203]
Is 1/2 an answer? That’s what I keep getting
7 0
2 years ago
Simplify the imaginary number sqr -75
m_a_m_a [10]

Answer:

5i\sqrt{3}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

and \sqrt{-1} = i

Given

\sqrt{-75}

= \sqrt{25(3)(-1)}

= \sqrt{25}  × \sqrt{3} × \sqrt{-1}

= 5 × \sqrt{3} × i

= 5i\sqrt{3}

3 0
3 years ago
If the circumference of a circle measures 5 pie cm, what is the area of the circle in terms of pie?
saw5 [17]

Answer:

6.25π cm²

Step-by-step explanation:

pi = π

Circumference = 5πcm

Now first we should find radius(r)

2πr = 5π cm

pie will be cancelled and we get here

r = 5/ 2 cm

Therefore r = 2.5 cm

Now

Area (A) = πr²

= π * 2.5²

= 6.25π cm²

4 0
3 years ago
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