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tatyana61 [14]
3 years ago
5

Which set of numbers best describes the possible values of x in the equation below?[x-1]=[x] all integer values of x all real nu

mber values of x only negative values of x only fractional values of x
Mathematics
2 answers:
natima [27]3 years ago
6 0

<u>Answer Choices:</u>

A) all integer values of x

B) all real number values of x

C) only negative values of x

D) only fractional values of x

<u>Answer:</u>

D

This is the correct answer on E2020.

SCORPION-xisa [38]3 years ago
3 0

[x] represents floor function also called as Greatest integer function.

Floor function is the function that takes as input a real number and gives as output the greatest integer less than or equal to.

like [1.5]=1

[0.7]=0

[-0.3]=-1

Now we have to find set of x-values which satisfies equation [x-1]=[x]

Due to -1 in [x-1], it always produces output value one less than value of [x]

for example when x=0.5 then [x]=[0.5]=0, [x-1]=[0.5-1]=[-0.5]=-1

when x=1.5 then [x]=[1.5]=1, [x-1]=[1.5-1]=[0.5]=0

when x=3 then [x]=[3]=3, [x-1]=[3-1]=[2]=2

From above results we can see that there is no value of x which satisfies the given equation [x-1]=[x]

Hence there is NO solution.

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A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

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x=\frac{-(40)}{2(-5)}

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x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

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Step-by-step explanation:

Given

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The greatest common factor of 12 and 6 is 6.
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