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maksim [4K]
3 years ago
6

The initial mass of a certain species of fish is 6 million tons. The mass of​ fish, if left​ alone, would increase at a rate pro

portional to the​ mass, with a proportionality constant of 2​/yr. ​However, commercial fishing removes fish mass at a constant rate of 15 million tons per year. When will all the fish be​ gone? If the fishing rate is changed so that the mass of fish remains​ constant, what should that rate​ be?

Mathematics
1 answer:
Phoenix [80]3 years ago
7 0

Answer:

Step-by-step explanation:

Check attachment for solution

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Which answer is correct!?!?
Naya [18.7K]
46%d+57%y=55%x42
x+y=42

Find y

x=42-y

46%(42-y)+57%y=23.1
19.31-46%y+57%y=23.1
11%y=23.1-19.31
11%y=3.79
y=34

The answer is D
6 0
3 years ago
( 6x ^2 - x + 3 ) +( - 2x + x^2 - 7 )​
alexandr1967 [171]

Answer:

7x² - 3x - 4

Step-by-step explanation:

<u>Step 1: Write expression</u>

(6x² - x + 3) + (-2x + x² - 7)

<u>Step 2: Combine like terms (x²)</u>

7x² - x + 3 - 2x - 7

<u>Step 3: Combine like terms (x)</u>

7x² - 3x + 3 - 7

<u>Step 4: Combine like terms (constants)</u>

7x² - 3x - 4

8 0
3 years ago
0.8+0.8=0.6k+0.9<br> What is k?
cluponka [151]
.6k+.9=1.6
.6k=.7
k=7/6= 1 1/6
k= 1 1/6
Hope this helps. 
6 0
3 years ago
Read 2 more answers
An equal number of pieces of candy were given to children on Halloween. 30 pieces of candy were given out to boys. 48 pieces of
scoray [572]

Answer:

6 pieces of candy

Step-by-step explanation:

Since an equal number of pieces of candy were given to children on Halloween, and obviously, a different amount of boys and girls were present on Halloween. Since 30 pieces of candy were given out to boys and 48 were given out to girls, a certain amount of candy was given to some amount of boys to equal 30, and that same amount of candy was given to another amount of girls to equal 48. Since we are looking for the greatest number of pieces given to each child, we are looking for the greatest common divisor of 30 and 48, which is 6.

4 0
2 years ago
PLZ HELP! VERY URGENT!<br> A line passes through (6,3), (8,4), and (n,-2). Find the value of n.
Phantasy [73]

We have a line passing through 3 points. We can use the first
two points to find the equation of the line.
(6,3), (8,4)

slope m = (4-3)/(8-6) = 1/2

We can use the point slope form y-y1 = m(x-x1) or
the slope intercept form y = mx + b
to find the equation of the line.

Let's take the point (6,3) and use y = mx + b to find b
y = 3, x = 6, m = 1/2

3 = (1/2)(6) + b
3 = 3 + b
0 = b

The equation of our line is y = (1/2)x

We have a line of equation y = (1/2)x going through point (n,-2)

Plugging in we have: -2 = (1/2)n
2(-2) = n
-4 = n

Your answer is n = -4

NOTE: looking at the 3 points as given initially: (6,3), (8,4), (n,-2)
We can see that 3 = (1/2)6 and 4 = (1/2)8 so -2 = (1/2)n makes sense

Hope this helps you :)
5 0
3 years ago
Read 2 more answers
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