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3 years ago

Which expression is equivalent to 5x + 7y

Mathematics

1 answer:

astra-53 [7]3 years ago

3 0

7y + 5x is another way to write it, is there anything specific you're looking for

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Help me for brainlest

SSSSS [86.1K]

Answer: y=3x+3 would be your answer

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2 years ago

Jill had $125 to spend at the mall. She spent 27% of that money on a pair of shoes. Jill spent $___ on the shoes.

zaharov [31]

You need to find what 27% of $125 is.
To find a percent of a number, multiply the percent by the number.

27% of $125 =

= 27% * $125

= 0.27 * $125

= $33.75

Answer: Jill spent $33.75 on the shoes.

4 0

3 years ago

The standard error is the ______ a variance of b variance of the sampling distribution of c standard deviation of the sampling d

skad [1K]

I think that is the mean or the mode . I think more on mean

6 0

3 years ago

Which of the following correctly expresses sin (70) + sin(30) as a product?

JulsSmile [24]

Answer:

2sin50 cos20

Step-by-step explanation:

We need to write sin (70) + sin(30) as a product. The formula used here is :

$\sin A+\sin B=2\sin (\dfrac{A+B}{2})\cos(\dfrac{a-b}{2})$

Here, A = 70 and B = 30

So,

$\sin 70+\sin 30=2\sin (\dfrac{70+30}{2})\cos(\dfrac{70-30}{2})\\\\\sin 70+\sin 30=2\sin 50\cos20$

So, the value of sin (70) + sin(30) is 2sin50 cos20. Hence, the correct option is (c).

7 0

3 years ago

I need help! Will mark Brainliest for full answer!!!

Softa [21]

Answer:

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

Explanation:

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

Mathematically, an inverse variation relation is represented as follows:

$y = \frac{k}{x}$

where x and y are the two variables and k is the constant of variation

Now, let's check the givens:

Part a:

We are given that y = 3 and k = 33

Substitute in the original relation and solve for x as follows:

$y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11$

Part b:

We are given that y = 11 and x = 5.2

Substitute in the original relation and solve for k as follows:

$y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2$

Part c:

We are given that x=7.8 and k=72

Substitute in the original relation and solve for y as follows:

$y=\frac{k}{x}=\frac{72}{7.8}=9.2$ to the nearest tenth

Hope this helps :)

6 0

3 years ago