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3 years ago

What is the value of y?

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Y + y + 60 = 180
2y + 60 = 180
2y = 120
y = 60
answer.
D. 60

tangare [24]3 years ago

4 0

Answer:

The correct option is D) 60°

Step-by-step explanation:

Consider the provided triangle.

From the provided figure it is given that one angle is 60° and we need to find the value of y.

As we know the sum of all interior angle in a triangle is 180°.

y°+y°+60°=180°

Now solve the above equation to find the value of y.

2y°+60°=180°

2y°=180°-60°

2y°=120°

y°=120°÷2

y°=60°

Hence, the value of y is 60°.

Thus, the correct option is D) 60°

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1.2÷182.4 what is the answer

Helga [31]

Answer:

0.0007

Step-by-step explanation:

6 0

3 years ago

Shelby paid $1.75 for a notebook at a big 75% off sale. What was the original price of the notebook?

Shkiper50 [21]

Answer:

$7.00

Step-by-step explanation:

The discount is 75% off. To answer this question, multiply n (the original price) by (1.00 - 0.75): 0.25n = $1.75.

Solving this for n, we get $7.00

3 0

3 years ago

I need help, pls can somebody help on this, it due this Friday

rusak2 [61]

Answer:

To express percentages in decimal form, you start with the decimal on the right side of the percentage, then you bring the decimal two places to the left. So for example, for 5% it it 5.. when you bring the decimal two places to the left it becomes .05

We start with $371.93 then we multiply each percentage successively to this number

we work backwards

so we start with 5%

$371.93= .95 x X

X=$391.51

Then we take X and do the same process for 10%

$391.51= .90 x Y

Y = $435.01

again we take Y and do the same process for 25%

$435.01= .75 x Z

Z = $580.01

so the original price is $580.01

to find the total percent discount you take the total discounted price ($371.93) divided by the original price ($580.01) then you have 1 subtracted by the number. Finally, you multiply the number by 100 to change it to a percentage

so it's $371.93/$580.01 which = .64125

1 - 64125 = .35875 x 100= 35.88%

so your total percent discount is 35.88%

Hope this helps

5 0

3 years ago

The distribution of weekly salaries at a large company is right skewed with a mean of $1000 and a standard deviation of $350. Wh

Shtirlitz [24]

Answer:

68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation, which is also called standard error $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 1000, \sigma = 350, n = 50, s = \frac{350}{\sqrt{50}} = 49.5$

What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

This is the pvalue of Z when X = 1000+50 = 1050 subtracted by the pvalue of Z when X = 1000-50 = 950. So

X = 1050

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$