Ok so remember
when 2 lines intersect the 2 opposite angles that face each other are equal measure
also, remember that a straight line=180
so
therefor BEA=CED and we want to find BEA, also
BED=180 so
BEC+CED=BED=180
aka
6x+7+5x-3=180
solve
6x+7+5x-3=180
combine
11x+4=180
subttract 4
11x=176
diivde 11
x=16
CED=AEB
CED=5x-3
subsitute
CED=5(16)-3
CED=80-3
CED=77
CED=77=AEB
answer is 77 degreees
Answer:
-0.43
Step-by-step explanation:
100/-43
ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
25+1=26 25x4=100 this is the answer
