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2 years ago

Don’t understand pls help

Mathematics

1 answer:

telo118 [61]2 years ago

8 0

Answer:

-1.5x + 3

Step-by-step explanation:

The Y-intercept is visible, wherever the line is touching the Y-Axes is the intercept. Use this formula to solve for slope:

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What is the perimeter of the fifth square in this pattern?

Rom4ik [11]

I think its 144 because its the fifth square

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3 years ago

Please help me!!!<br><br><br> What reason belongs to step 10?

castortr0y [4]

SAS

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3 years ago

Michelle is 7 years older than her sister Joan, and Joan is 3 years younger than their brother Ryan. If the sum of their ages is

Zielflug [23.3K]

Answer:

Step-by-step explanation:

We can create a systems of equations. Assuming $m$ is Michelle's age, $j$ is Joan's age, and $r$ is Ryan's age, the equations are:

$m = j + 7$

$j = r-3$

$m+j+r = 64$

We can use substitution, since we know the "values" of m and j.

$(j+7)+(r-3)+r = 64\\(j+7)+(2r-3)=64\\2r + j + 4 = 64\\2r + j = 60\\\\$

$r = 21, j = 18$

So we know that Joan is 18 years old.

Hope this helped!

8 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

Find the missing factor $6.50. =$65

babymother [125]

1) $65 ÷ $6.50 = $10
2) Check Work: $10 × $6.50 = $65
$10 is your missing factor :)
Hope This Helps :)

6 0

3 years ago

Read 2 more answers