How many ways can a group of 8 students be selected from 9 students?
1 answer:
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Answer:
Option D, I agree with neither Elena nor Lin
Step-by-step explanation:
The remaining part of the question is attached herewith
Solution
As we can see in the image
ED is perpendicular to AB and BC is perpendicular to AB
Thus, as per the Pythagoras theorem,
AC^2 = AB^2 + BC^2
14^2 = 6^2 + BC^2
BC^2 = 196-36 = 160
BC = 12.649 OR 12.65
Hence, option D
I agree with neither Elena nor Lin
