Answer: £122.4
Step-by-step explanation:
Given
The rate of interest is 4%
The principal invested is £1500
the time period is 2 years
Compound interest is given by
put values
![C.I.=1500(1+0.04)^2-1500\\C.I.=1500[1.04^2-1]\\C.I.=1500[1.0816-1]\\C.I.=1500\times 0.0816\\C.I.=122.4](https://tex.z-dn.net/?f=C.I.%3D1500%281%2B0.04%29%5E2-1500%5C%5CC.I.%3D1500%5B1.04%5E2-1%5D%5C%5CC.I.%3D1500%5B1.0816-1%5D%5C%5CC.I.%3D1500%5Ctimes%200.0816%5C%5CC.I.%3D122.4)
Therefore, interest earned is £122.4
Answer:
D
Step-by-step explanation:
Because I know
As you see in the picture, there are two lines that could maybe represent two linear functions. However, this is not true because of the solid point and the hollow point. This is an inequality equation that has points of discontinuity.
Points of discontinuity are breaks in the graph that are a result of an undefined point when the f(x) is substituted with a point of x that is not part of the solution. So, technically, the graph is made from one rational expression.
So, when it says f(-2), this is the y-value at x=-2. That means f(-2)=2, f(0)=3 and f(4)=-1. Specifically, there are two points at x=0, but we take the solid point only.
Descending order...largest to smallest
the largest one is the one with the biggest exponent
so the first term is : 7z^4
Answer:
13.20 min
Step-by-step explanation:
Rate of the reaction is a measure of the rate of decomposition of the compound.
Rate (R) = Concentration (C) ÷ time (t)
C1/t1 = C2/t2
C1 = 52.3% = 0.523
t1 = 8.6 min
C2 = 80.3% = 0.803
t2 = C2t1/C1 = 0.803×8.6/0.523 = 13.20 min (to 2 decimal places)
