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yaroslaw [1]
3 years ago
10

Please help me asap!

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:   1. ∠A= 80.75°  2. 41.79 cm^2

Step-by-step explanation:

Since, According to the sines low,

\frac{sin A}{CB} = \frac{sin C}{AB}

Here, CB= 4.1 cm,  AB = 3.3 and ∠ C = 52.6°

\frac{sin A}{4.1} = \frac{sin 52.6}{3.3}

⇒ sin A = 4.1\times\frac{sin 52.6}{3.3}

⇒  sin A =0.98699998308

⇒ A = 80.75°

2. Since, the area of the given figure = Area of the rectangle having dimension 8.3 × 4.2 + Area of the half square of radius 2.1

=34.86 + 6.93

= 41.79 square cm

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To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

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Now, considering the isosceles triangle OQR, we have that:

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