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tatyana61 [14]
3 years ago
7

Mistletoe is a plant that lives on trees and gains nutrition from them (that is, it is a parasite). the fruit of the mistletoe i

s a one-seeded berry and is consumed by birds. in members of the genus viscum, the outside of the seed is viscous (sticky), which permits the seed to adhere to surfaces such as the branches of host plants or the beaks of birds. what should be expected of the fruit if the viscosity of viscum seeds is primarily an adaptation for dispersal rather than an adaptation for infecting host plant tissues? the fruit ________.
Biology
1 answer:
Pepsi [2]3 years ago
6 0

Ans.

<em>Viscum album </em>is a plant species, commonly known as mistletoe. It is a hemi-parasitic plant that grows on other trees.

Birds cause seed dispersal as they pick seeds from parent plant and drop them in other places. Seeds of mistletoe are sticky or viscous due to mucus and they provide nutritious food to the birds.

Hence, it can be concluded that the mistletoe seeds show adaptations primarily for seed dispersion, not for infecting the host plant.

Thus, the correct answer to be filled in the blank is 'is nutritious to the dispersing birds.'

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Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given
alexandr402 [8]

Use the slope-intercept form to find the slope.

Tap for fewer steps...

The slope-intercept form is  

y = m x + b  

where  m  is the slope and  b  is the y-intercept.

y = m x + b  

Using the slope-intercept form the slope is  

− 4 . m = − 4

To find an equation that is parallel to  

y = − 4 x + 2

the slopes must be equal. Using the slope of the equation, find the parallel line using the point-slope formula.

( − 2 , 5 ) m = − 4

Using the point-slope form  

y − y 1 = m ( x − x 1 )

plug in  

m = − 4 ,  x 1 = − 2

and  

y 1 = 5 . y − ( 5 ) = ( − 4 ) ( x − ( − 2 ) )

Solve for  

y .

Multiply  

− 1  by  5 . y − 5 = ( − 4 ) ( x − ( − 2 ) )

Simplify  

( − 4 ) ( x − ( − 2 ) ) .

Multiply  

− 1  by  − 2 . y − 5 = − 4 ( x + 2 )

Apply the distributive property.

y − 5 = − 4 x − 4 ⋅ 2

Multiply  − 4  by  2 . y − 5 = − 4 x − 8

Move all terms not containing  

y  to the right side of the equation.

Add  

5

to both sides of the equation.

y = − 4 x − 8 + 5  Add  − 8  and  5 . y = − 4 x − 3

HOPE THIS HELPED!

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Explanation:

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