When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)
Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:
• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]
• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]
• bisecting an arbitrary interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
gives the intervals ![\left[a,\frac{a+b}2\right]](https://tex.z-dn.net/?f=%5Cleft%5Ba%2C%5Cfrac%7Ba%2Bb%7D2%5Cright%5D)
and ![\left[\frac{a+b}2,b\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Ba%2Bb%7D2%2Cb%5Cright%5D)
Answer:
Step-by-step explanation:
Let the price for children and adults package be represented with x and y respectively.
For the first week the sum of the package will be as follows:
3x+8y = 126
For the two weeks after:
6x+4y= 108
So, we will be having two equations
3x+8y = 126..... (1)
6x+4y= 108.......(2)
These are simultaneous equations
From equation 1
3x+8y = 126
3x = 126-8y
X = 126-8y/3 ............. (3)
Put equation 3 into 2
6 ( 126-8y)/3 +4y = 108
756-48y/3 +4y = 108
756-48y+12y/3 = 108
Cross multiplying
756-48y+12y= 108×3
756-48y+ 12y = 324
Collecting like terms
756-324 = 48y-12y
432= 36y
Divide both sides by 36
432/36 = 36y/36
y= 12
Substituting y into equation 1
3x+8= 126
3x+96=126
3x= 126-96
3x= 30
Divide both sides by 3
3x/3 = 30/3
x = 10
Hence for each of the packages for children and adults. It will be 10 and 12 respectively.
The first one is the last answer because you subtract 18 and when you divide you change the inequality symbol
the second one is the last answer for the same reason
the 3rd one is x<-1.25
the 4th one is x<8/15
The answer is 22 because the 5t and -5t cancel each other
It would be 0.2222 so it's your answer
