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2 years ago

6

What is the same of the data? skewed right skewed left symmetrical not enough info

1 answer:

Solnce55 [7]2 years ago

5 0

Hi djdjfjfjfjfjgjtificnfnfnfjfj

You might be interested in

Let's say the probability of you winning a game of checkers and a game of chess against your friend is 20%. The probability of y

GREYUIT [131]

The probability of winning a game of checkers against your friend is 67%.

<h3>What is the probability of winning a game of checkers against my friend?</h3>

Probability can be described as the process of determining the chances of an event happening. The chances that an event would occur has a value that lies between 0 and 1. A value of 0 is given when the event does not occur and a value of 1 if the event occurs.

The probability of winning a game of checkers = probability of winning both games / probability of winning a game of chess

20% / 30% = 67%

To learn more about probability, please check: brainly.com/question/26321175

8 0

2 years ago

What is the measurement of angle g?

lisov135 [29]

Answer:

The answer is 26

Step-by-step explanation:

64+ 90= 154. 180-154=26, your missing angle

5 0

3 years ago

Can someone explain the process of getting to Angle A? I know the answer is 44.1 but I need to show my work so can someone show

dsp73

Answer:

Step-by-step explanation:

First you have to calculate CB in order to use sin law to calculate ∠A

CB= $\sqrt{18.4^{2} -13.2^{2} }$

CB=12.8(correct to nearest tenth)

After that, use sin law to calculate ∠A,

$\frac{18.4}{sin90} =\frac{12.8}{sinA}$ or $\frac{sin90}{18.4} =\frac{sinA}{12.8}$

sinA=0.695...

A=44.079...

=44.1(corrext to the nearest tenth)

Is that clear enough for you?

4 0

2 years ago

If y= 3x + 6, what is the minimum value of (x^3)(y)?

Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of $(x^3)(y)$

Let f(x) = $(x^3)(y)$

Substitute the value of y ;

$f(x)=(x^3)(3x+6)$

Distribute the terms;

$f(x)= 3x^4 + 6x^3$

The derivative value of f(x) with respect to x.

$\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)$

Using $\frac{d}{dx}(x^n) = nx^{n-1}$

we have;

$\frac{df}{dx} =(12x^3+18x^2)$

Set $\frac{df}{dx} = 0$

then;

$(12x^3+18x^2) =0$

$6x^2(2x + 3) = 0$

By zero product property;

$6x^2=0$ and 2x + 3 = 0

⇒ x=0 and x = $-\frac{3}{2} = -1.5$

then;

at x = 0

f(0) = 0

and

x = -1.5

$f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625$

Hence the minimum value of $(x^3)(y)$ is, -5.0625

3 0

3 years ago

Multiply, if possible.

Ostrovityanka [42]

Answer:

2

3

-5

0

Step-by-step explanation:

2×0+1×2=2

2×1+1×1=3

2×-3+1×1=-5

2×-2+1×4=0

7 0

3 years ago

Read 2 more answers