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Elanso [62]
2 years ago
6

What is the same of the data? skewed right skewed left symmetrical not enough info

Mathematics
1 answer:
Solnce55 [7]2 years ago
5 0
Hi djdjfjfjfjfjgjtificnfnfnfjfj
You might be interested in
Let's say the probability of you winning a game of checkers and a game of chess against your friend is 20%. The probability of y
GREYUIT [131]

The probability of winning a game of checkers against your friend is 67%.

<h3>What is the probability of winning a game of checkers against my friend?</h3>

Probability can be described as the process of determining the chances of an event happening. The chances that an event would occur has a value that lies between 0 and 1. A value of 0 is given when the event does not occur and a value of 1 if the event occurs.

The probability of winning a game of checkers = probability of winning both games / probability of winning a game of chess

20% / 30% = 67%

To learn more about probability, please check: brainly.com/question/26321175

8 0
2 years ago
What is the measurement of angle g?
lisov135 [29]

Answer:

The answer is 26

Step-by-step explanation:

64+ 90= 154. 180-154=26, your missing angle

5 0
3 years ago
Can someone explain the process of getting to Angle A? I know the answer is 44.1 but I need to show my work so can someone show
dsp73

Answer:

Step-by-step explanation:

First you have to calculate CB in order to use sin law to calculate ∠A

CB=\sqrt{18.4^{2} -13.2^{2} }

CB=12.8(correct to nearest tenth)

After that, use sin law to calculate ∠A,

\frac{18.4}{sin90} =\frac{12.8}{sinA}       or    \frac{sin90}{18.4} =\frac{sinA}{12.8}

sinA=0.695...

A=44.079...

  =44.1(corrext to the nearest tenth)

Is that clear enough for you?

4 0
2 years ago
If y= 3x + 6, what is the minimum value of (x^3)(y)?
Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of (x^3)(y)

Let f(x) = (x^3)(y)

Substitute the value of y ;

f(x)=(x^3)(3x+6)

Distribute the terms;

f(x)= 3x^4 + 6x^3

The derivative value of f(x) with respect to x.

\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)

Using \frac{d}{dx}(x^n) = nx^{n-1}

we have;

\frac{df}{dx} =(12x^3+18x^2)

Set \frac{df}{dx} = 0

then;

(12x^3+18x^2) =0

6x^2(2x + 3) = 0

By zero product property;

6x^2=0   and 2x + 3 = 0

⇒ x=0 and x = -\frac{3}{2} = -1.5

then;

at x = 0

f(0) = 0

and  

x = -1.5

f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625


Hence the minimum value of (x^3)(y) is, -5.0625






3 0
3 years ago
Multiply, if possible.
Ostrovityanka [42]

Answer:

2

3

-5

0

Step-by-step explanation:

2×0+1×2=2

2×1+1×1=3

2×-3+1×1=-5

2×-2+1×4=0

7 0
3 years ago
Read 2 more answers
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