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ipn [44]
3 years ago
15

An element’s mass number tells the number of protons in its nucleus true or false?

Physics
2 answers:
Vanyuwa [196]3 years ago
7 0
Yes, this statement is true!
Tamiku [17]3 years ago
5 0

Answer:

true

...................................

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Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor whe
spin [16.1K]
Average velocity =

      (displacement) / (time for the displacement)
and
      (direction of the displacement) .

Displacement =

      (distance from the start-point to the end-point)
and
      (direction from the start-point to the end-point)   .

When Ben is 200 meters from the corner store,
he is (500 - 200) = 300 meters from his house.

His displacement is

         300 meters in the direction
                             from his house to the neighbor .


His average velocity is

         (300/910) =  0.33 meters per second, in the
                               direction from his house to the neighbor .


7 0
3 years ago
Read 2 more answers
Select the correct answer. What is tan for the given triangle? 0.60 1.67 1.33 5.00 0.20
GuDViN [60]
The answer is 1.33 i hope this helps you
8 0
3 years ago
Read 2 more answers
A 6 kg box with initial speed 5 m/s slides across the floor and comes to a stop after 1.9 s. What is the coefficient of kinetic
Ilia_Sergeevich [38]

Answer:

\mu_k=0.27

Explanation:

According to the free body diagram, in this case, we have:

\sum F_x:-F_k=ma\\\sum F_y:N=mg

Recall that the force of friction is given by:

F_k=\mu_k N

Replacing and solving for the coefficient of kinetic friction:

-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}

We have an uniformly accelerated motion. Thus, the acceleration is defined as:

a=\frac{v_f-v_0}{t}\\a=\frac{0-5\frac{m}{s}}{1.9s}\\a=-2.63\frac{m}{s^2}

Finally, we calculate \mu_k:

\mu_k=-\frac{-2.63\frac{m}{s^2}}{9.8\frac{m}{s^2}}\\\mu_k=0.27

4 0
3 years ago
A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio
Maurinko [17]
The answer is D hoped this helped
4 0
3 years ago
Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object
user100 [1]

For 3 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{3kg} = 4\lpha m / s^{2}</em>

For 6 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{6kg} = 2\lpha m / s^{2}</em>


Hope this helped, have a great day!~

3 0
3 years ago
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