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Alina [70]
2 years ago
15

The paths of the light waves that interfere to cause first-order lines (2 points) Group of answer choices differ in length by th

e wavelength of the light are parallel lines are the same length differ in length by one-half of the wavelength of the light
Physics
1 answer:
Zarrin [17]2 years ago
6 0

The paths of the light waves that interfere cause first-order lines to differ in length by the wavelength of the light.

The phenomenon of wave interference occurs when two waves meet while traveling in the same medium.

As the two light waves interfere in the first order they interfere by differing the consecutive lengths by the wavelength of the light. The wavelength of the light can be defined as the distance between identical points (adjacent crests) in the adjacent cycles of a wave signal propagated in space or along a wire.

Hence, it can be concluded that the paths of the light waves that interfere cause first-order lines to differ in length by the wavelength of the light.

Learn more about waves here:

brainly.com/question/15663649

#SPJ10

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Stels [109]

Answer:

c

Explanation:

7 0
3 years ago
An object 1 of mass m1 is separated by some distance d from an object 2 of mass 2m1 . An object 3 of mass m3 is to be placed bet
Harrizon [31]

If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?

If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?

 

Object 3 should be placed closer to object 1.

 

Object 3 should be placed on a halfway between object 2 and object 1.

 

Object 3 should be placed closer to object 2.

 

Solution

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Una persona A tiene cierta cantidad de masa y una persona B tiene la mitad de masa de la persona A ¿como es el peso de B respect
musickatia [10]

Answer:

El peso de la persona B es la mitad del peso de la persona A.

Explanation:

El peso de la persona B puede calcularse con la siguiente ecuación:

P_{B} = m_{B}g   (1)

En donde:

m_{B}: es la masa de la persona B

g: es la gravedad

Dado que la persona B tiene la mitad de la masa de la persona A, tenemos:

m_{B} = \frac{m_{A}}{2}  (2)

En donde:

m_{A}: es la masa de la persona A

Al introducir la ecuación (2) en (1) nos queda:

P_{B} = \frac{m_{A}}{2}g   (3)

Sabemos que el peso de la persona A está dado por:

P_{A} = m_{A}g   (4)

Entonces, al introducir la ecuación (4) en (3) tenemos:

P_{B} = \frac{P_{A}}{2}

Por lo tanto, el peso de la persona B es la mitad del peso de la persona A.

Espero que te sea de utilidad!

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Elena-2011 [213]
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