Two technicians are discussing the need for the history of the vehicle. Technician A says that an accident could cause faults du
1 answer:
You might be interested in
the potential at the center of curvature of the arc = v = Q ∕ (4πε∘a) or
ATQ,
We have density of charge,
λ =
Where L is the rod's length, in this case the semicircle's length L = πr
Q is the charge on the rod
The potential created at the center by an differential element of charge is:
where k is the coulomb's constant
r is the distance from dQ to center of the circle
v = ∫ , Where a = radius, k = 1 / 4πε∘
v = or Q ∕ (4πε∘a)
To learn more about potential from the given link
#SPJ4
Answer:
Explanation:
Charge of particle = q
The particles have same charge
r = Distance between charge
k = Coulomb constant =
m = Mass of particle = 10 mg
g = Acceleration due to gravity = 9.81 m/s²
Electrostatic force is given by
According to Newton's second law
Here, both the electrostatic and inertial force is conserved
The charge of the particles is
The charge of the particles is very low as compared to typical static electricity