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VikaD [51]
4 years ago
5

Please help ASAP!! I need a good grade on this!!!!

Physics
1 answer:
svet-max [94.6K]4 years ago
6 0

Answer:

1A) 3kg * m/s

2D) 100

3, Guess: A smaller change of momentum

4, Guess: A, 1.80

5B) 20

Explanation:

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If the potential due to a point charge is 5.05 ✕ 102 V at a distance of 15.7 m, what are the sign and magnitude of the charge? (
aleksklad [387]

Answer:

The magnitude of charge is 8.809\times 10^{-7}\ C with a positive charge.

Explanation:

Given that,

The potential due to a point charge, V=5.05\times 10^2\ V

Distance, d = 15.7 m

The potential due to a point charge is given by :

V=\dfrac{kq}{d}

q is charge

k is electrostatic constant

q=\dfrac{Vd}{k}\\\\q=\dfrac{5.05\times 10^2\times 15.7}{9\times 10^9}\\\\q=8.809\times 10^{-7}\ C  

Here, the potential is positive, then the magnitude of charge is 8.809\times 10^{-7}\ C with a positive charge.

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The major winds for the cities that are located at latitudes of 35 degrees north are prevailing winds and westerlies. Prevailing winds are winds that blow in a single direction. Westerlies are prevailing winds that blow towards the west side of the Earth.
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When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmin
Andre45 [30]

Answer:

V=12.1622\ L

Explanation:

Given:

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<em>Now, let </em><em>m </em><em>be the mass of water at zero degree Celsius to be drank to spend 450 kilo-calories of energy.</em>

We know:

Q=m.c.\Delta T .....................................(1)

where:

m = mass of water

Q = heat energy

\Delta T= temperature difference

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<u>Putting values in the eq. (1):</u>

1883700=m\times 4186\times 37

m=12.1622\ kg

Since water has a density of 1 kilogram per liter, therefore the volume of water will be:

V=12.1622\ L

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Which free body diagram is in equilibrium?
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A. because everything is balanced.

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A sample of the mineral calcite has a volume of 15 cm³ and a mass of 40.5 g. What is the density of the calcite?
koban [17]
Density=mass÷volume
density=40.5÷15=2.7
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