Answer:
$61.23
Explanation:
$38.85 + $22.38 = $61.23
I'm thinking its a im not sure though since i just finished getting out of that unit
Answer:
a. the line that makes the sum of the squares of the vertical distances of the data points from the line (the sum of squared residuals) as small as possible.
Step-by-step explanation:
If we have N points
and we want to adjust a model 
We can define the error associated to this like that:
![E(a,b) = \sum_{n=1}^N [y_n -(ax_n +b)]^2](https://tex.z-dn.net/?f=%20E%28a%2Cb%29%20%3D%20%5Csum_%7Bn%3D1%7D%5EN%20%5By_n%20-%28ax_n%20%2Bb%29%5D%5E2)
So as we can see here we are adding the square distances between the real and the adjusted values in order to minimize the error for this reason the correct answer is:
a. the line that makes the sum of the squares of the vertical distances of the data points from the line (the sum of squared residuals) as small as possible.
For this case we need to calculate the slope with the following formula:
Where:
And we can find the intercept using this:
The probability of losing a data packet is 0.010.
Therefore the probability of successfully sending a data packet (not losing a data packet) is
p = 1 - 0.010 = 0.99
In 100 packet transmissions (independent events), the probability of success is
0.99¹⁰⁰ = 0.3660
The probability of losing a data packet is
1 - 0.366 = 0.6340
Answer:
The probability of resending a data packet is 0.6340
|-5| - |7 - 4|
First, simplify |-5| to 5. / Your problem should look like: 5 - |7 - 4|
Second, simplify 7 - 4 to 3. / Your problem should look like: 5 - |3|
Third, simplify. / Your problem should look like: 2
Answer: 2