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8090 [49]
3 years ago
9

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x

+ y - 2 = 0?
answers:
4x - y = 13
4x + y = 13
4x + y = -13
Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

The equation of this line would be 4x + y = 13

Step-by-step explanation:

In order to find this equation we must first find the slope of the original line. To do this, we solve the original equation for y.

4x + y - 2 = 0

4x + y = 2

y = -4x + 2

The original slope (the coefficient of x) is -4, which means the new slope will also be -4 because parallel lines have the same slope. Now, we can use this slope along with the point in point-slope form to find the equation of the line. Just plug in the numbers and solve for the coefficient.

y - y1 = m(x - x1)

y + 3 = -4(x - 4)

y + 3 = -4x + 16

4x + y + 3 = 16

4x + y = 13

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Write the equation in point-slope form of the line that passes through the given point and has the given slope (4,-7); m= -1/4
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Answer:

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General Formulas and Concepts:

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)  

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  • y₁ - y coordinate
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Step-by-step explanation:

<u>Step 1: Define</u>

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Point (4, -7)

<u>Step 2: Write Function</u>

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therfor
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