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Morgarella [4.7K]

3 years ago

12

NEED HELP FAST PLEASE!

1 answer:

timofeeve [1]3 years ago

3 0

Answer: Choice A. It travels for 1 hour, stops for 1 hour, then travels for 3 hours

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Any portion of the graph that isn't flat and horizontal is when the car is traveling. In this case, it's the portion from x = 0 to x = 1 (the first hour of travel) and the portion from x = 2 to x = 5 (the final three hours of travel). The flat portion starts at x = 1 and stops at x = 2. So this represents 1 hour of rest. This is where the distance (y) isn't changing.

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What is the slope of a line parallel to a line with equation 2x - 5y = 9

Aleonysh [2.5K]

First take and get the slope of the line. If the slope is equal to an option then that's your answer. Hope I helped!

5 0

3 years ago

Solve the inequality:<br> 2[(2y-1)+y] less than or equal to 5(y+3)

Likurg_2 [28]

$2[(2y-1)+y]\leq5(y+3)\\\\2(2y-1+y)\leq5(y+3)\\\\2(3y-1)\leq5(y+3)\ \ \ |use\ distributive\ property:a(b\pm c)=ab\pm ac\\\\2(3y)-2(1)\leq5(y)+5(3)\\\\6y-2\leq5y+15\ \ \ |add\ 2\ to\ both\ sides\\\\6y\leq5y+17\ \ \ \ |subtract\ 5y\ from\ both\ sides\\\\\huge\boxed{y\leq17\to y\in(-\infty;\ 17]}$

8 0

3 years ago

larisa [96]

Answer:

14.9cm

Step-by-step explanation:

20sin40= b

b= 14.9022

b = 14.9cm

5 0

3 years ago

when inches are converted to centimeters, is the number of centimeters greater than the number of inches?

Gnom [1K]

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4 0

3 years ago

In 2000 the population of a country reached 1 billion, and in 2025 it is projected to be 1.2 billion. (a) Find values for C an

Mice21 [21]

Answer:

(a) The value of C is 1.

(b) In 2010, the population would be 1.07555 billions.

(c) In 2047, the population would be 1.4 billions.

Step-by-step explanation:

(a) Here, the given function that shows the population(in billions) of the country in year x,

$P(x)=Ca^{x-2000}$

So, the population in 2000,

$P(2000)=Ca^{2000-2000}$

$=Ca^{0}$

$=C$

According to the question,

$P(2000)=1$

$\implies C=1$

(b) Similarly,

The population in 2025,

$P(2025)=Ca^{2025-2000}$

$=Ca^{25}$

$=a^{25}$ (∵ C = 1)

Again according to the question,

$P(2025)=1.2$

$a^{25}=1.2$

Taking ln both sides,

$\ln a^{25}=\ln 1.2$

$25\ln a = \ln 1.2$

$\ln a = \frac{\ln 1.2}{25}\approx 0.00729$

$a=e^{0.00729}=1.00731$

Thus, the function that shows the population in year x,

$P(x)=(1.00731)^{x-2000}$ ...... (1)

The population in 2010,

$P(2010)=(1.00731)^{2010-2000}=(1.00731)^{10}=1.07555$

Hence, the population in 2010 would be 1.07555 billions.

(c) If population P(x) = 1.4 billion,

Then, from equation (1),

$1.4=(1.00731)^{x-2000}$

$\ln 1.4=(x-2000)\ln 1.00731$

$0.33647 = (x-2000)0.00728$

$0.33647 = 0.00728x-14.56682$

$0.33647 + 14.56682 = 0.00728x$

$14.90329 = 0.00728x$

$\implies x=\frac{14.90329}{0.00728}\approx 2047$

Therefore, the country's population might reach 1.4 billion in 2047.

3 0

3 years ago