All categories

3 years ago

How are astronomers able to observe and study black holes?

1 answer:

Ber [7]3 years ago

5 0

Although scientists can't detect or observe black holes with telescopes that detect x-rays, light, or other many other different forms of electromagnetic radiation and waves. But they can detect and study them by the effect of matter near it. If a black hole passes through a cloud of interstellar matter, it will draw matter inward (this process is known as accretion). A similar process occurs when a star passes through a black hole. When this happens, a star can break apart as it pulls it self toward it. As the attracted matter accelerates and starts heating up, it emits x-rays that are radiate into space.
Recent studies do show that black do have a very big influence towards neighborhoods around it. The black hole emits gamma ray bursts, devouring nearby stars, and spurring the growth of new stars in some areas while stalling it in others.

Info: https://science.nasa.gov/astrophysics/focus-areas/black-holes

Hope this Helps! (:

You might be interested in

Explain why two acetate rods, both charged with silk repel

kenny6666 [7]

Two acetate rods, both charged with silk would repel because they are both have positively charged electrons.

Explanation: Opposite charges attract. Like charges repel.

8 0

3 years ago

When sound waves travel through a medium, the particles of the medium move parallel to the wave motion. Which type of wave displ

NemiM [27]

Forgot answer choices but it would be LONGITUDINAL WAVES<span />

3 0

3 years ago

Read 2 more answers

The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60 cm ) sin ( 6.20 y+ 60.0 t ), where y is in m

trapecia [35]

Answer:

The question is incomplete, below is the complete question

"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.

A) What is the frequency of this wave?

B) What is the wavelength of this wave?

C) What is the speed of this wave?"

Answers:

a. $f=\frac{30}{\pi }Hz\\$

b. $wavelength=\frac{\pi }{3.1}m \\$

c. $v=9.68m/s$

Explanation:

The equation of a wave is represented as

$D(x,t)=Asin(kx+wt) \\$

Where A=amplitude

w=angular frequency=2πf

K=wave numbers =2π/λ

since we re giving he equation D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),

we can compare and get the value for the wave number and angular frequency.

By comparing we have

w=60rads/s

k=6.20

a. to determine the frequency, from the expression fr angular wave frequency we have

w=2πf hence

f=w/2π

if we substitute we arrive at

$f=\frac{60}{2\pi }\\f=\frac{30}{\pi }Hz\\$

b. to determine the wave length, we use

$k=\frac{2\pi }{wavelength} \\k=6.2\\wavelength=\frac{2\pi }{k} \\wavelength=\frac{2\pi }{6.2} \\wavelength=\frac{\pi }{3.1}m \\$

c. the wave speed v is express as the product of the frequency and the wavelength. Hence

$v=frequency*wavelength \\v=\frac{30}{\pi } *\frac{\pi }{3.1}\\ v=9.68m/s$

6 0

3 years ago

In the steady state 1.2 ✕ 1018 electrons per second enter bulb 1. There are 6.3 ✕ 1028 mobile electrons per cubic meter in tungs

bekas [8.4K]

Answer:

E=12.2V/m

Explanation:

To solve this problem we must address the concepts of drift velocity. A drift velocity is the average velocity attained by charged particles, such as electrons, in a material due to an electric field.

The equation is given by,

$V=\frac{I}{nAq}$