Science please help!

I need this done by tonight!! Can anyone help me please? Answer these 4 questions

VikaD [51]

Answer:

1. 14 g of chocolate mixture.

2. 24 fl oz of chocolate milk

3. 10 cups of chocolate milk.

4. 12½ cups.

Explanation:

From the question given above, the following data were obtained:

1 TBSP = 7 g

1 Cup = 8 fl oz

2 Table spoons (TBSP) for 1 cup (8 fl oz) of milk.

1. Determination of the mass of chocolate mixture in 1 cup of chocolate milk.

From the question given above,

1 Cup required 2 Table spoons (TBSP)

But

1 TBSP = 7 g

Therefore,

2 TBSP = 2 × 7 = 14 g

Thus, 1 Cup required 14 g of chocolate mixture.

2. Determination of the number fl oz of chocolate milk in 3 cups

1 Cup = 8 fl oz

Therefore,

3 Cups = 3 × 8

3 Cups = 24 fl oz

Thus, 24 fl oz of chocolate milk are in 3 cups.

3. Determination of the number of cups of chocolate milk produce from 20 TBSP.

2 TBSP is required to produce 1 cup.

Therefore,

20 TBSP will produce = 20/2 = 10 Cups.

Thus, 10 cups of chocolate milk produce from 20 TBSP.

4. Determination of the number of cups obtained from 100 fl oz chocolate milk.

8 fl oz is required to produce 1 cup.

Therefore,

100 fl oz will produce = 100 / 8 = 12½ cups.

Thus, 12½ cups is obtained from 100 fl oz chocolate milk.

4 0

3 years ago

While two forces act on it, a particle of mass m=3.2kg is it to move continuously with velocity (3m/s)i - (4m/s)j . one of the f

marta [7]

Mmm tricky.
Since the velocity is constant, I'm going to assume there is no acceleration in any direction. This means there is no net force in the I or J forection!

Since there are 2 forces, both must be equal and opposite in direction to perfectly cancel each other out.

So the opposite of F1 is (-2N)I + (6N)J!

8 0

4 years ago

How can you can tell if a fat is saturated?

Tpy6a [65]

Here is how you can tell if a fat is saturated or not:

It has to stay normal at room temperature and melt when heated.

Here is an example for you:

If there is a fat that stays normal when it is outside, but melts when heated, it is a saturated fat. It did what every other saturated fat would do.

Carry on Learning!

5 0

4 years ago

A centripetal force of 5.0 newtons is applied to a rubber stopper moving at a constant speed in a horizontal circle. If the same

mezya [45]

Answer:

Both the frequency f and velocity v will increase.

When the radius reduces, the circumference of the circular path becomes smaller which means that more number of revolutions can be made per unit time as long as the force is kept constant; this is an increase in frequency.

Explanation:

The centripetal force acting on a mass in circular motion is given by equation (1);

$F_c=\frac{mv^2}{r}....................(1)$

where m is the mass of the object and r is radius of the circle. From equation one we see that the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.

However, according to the problem, the force is constant while the radius and the velocity changes. Therefore we can write the following equation;

$\frac{mv_1^2}{r_1}=\frac{mv_2^2}{r_2}......................(2)$