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Paha777 [63]
3 years ago
9

Which pair of labels is correct? A: Maximum kinetic energy C: Maximum gravitational potential energy B: Maximum kinetic energy D

: Maximum gravitational potential energy A: Maximum gravitational potential energy C: Maximum kinetic energy B: Maximum gravitational potential energy D: Maximum kinetic energy
Physics
2 answers:
MAVERICK [17]3 years ago
5 0

Answer: C. A:Maximum gravitational potential energy C: Maximum kinetic energy

Explanation:

RUDIKE [14]3 years ago
4 0
Maximum kinetic enerygy
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a capacitor is connected accross a bettery? why does each plate recieve a charge of equal to magnitude?
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Differences between plastic and metal​
beks73 [17]

Answer:

Differences are listed below:

Explanation:

Weight: Plastic can weigh appreciably much less than than metal.A plastic part weighs approximately one-sixth of the same part in steel.

Chemical resistance:Plastic are much less likely to suffer chemical attack and don not corrode.

Machinability: Plastic are much more easier to cut through than metal.

Product life: The life span for plastic is longer than of the metals in many applications.

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6 0
3 years ago
Please help me to find what the factors affecting gravity are. 10 points !
Nataly [62]

Answer:

Universal Gravitation, it is a force that keeps the moon orbiting around earth (or you could also add "it is the force that keeps all planets in our solar system orbiting around the sun.'

Explanation:

Well, my teacher taught me that the "Big blue title" is the question and the "red title" would be your answer.

(I hope this helps! and i'm sorry if the answer is wrong.)

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4 0
3 years ago
A mass weighing 30 lbstretches a spring . The mass is also attached to a damper with coefficient . Determine the value of for wh
LUCKY_DIMON [66]

Answer:

the damping coefficient when the system is critically damped is 13.42 lb s/ft.

Explanation:

The directions are missing the last part, which is:

"A mass weighing 30 lb stretches a spring 7.5 in. The mass is also attached to a damper with coefficient γ. Determine the value of γ for which the system is critically damped. Assume that g = 32 \cfrac {ft}{s^2}

Round your answer to three decimal places."

The spring system is determined by the following differential equation

my''+\gamma y'+ky=0

where \gamma is the damping coefficient, thus it is critically damped when the system transitions from real to complex solutions that happens at

\gamma_^2 -4km=0

Solving for the damping coefficient.

\gamma^2 = 4km\\ \gamma = \sqrt{4km}

where the spring constant k is given by

k = \cfrac{mg}{L}\\k = \cfrac wL\\

And the mass is given by

mg = w\\ m = \cfrac wg

So the damping coefficient will be

\gamma = \sqrt{4\cfrac wL \cfrac wg}\\\gamma = \sqrt{4\cfrac {w^2}{gL}}

Replacing the given information we have:

\gamma = \sqrt{4\cfrac {(30\, lbs)^2}{32\cfrac{ft}{s^2}0.625 ft}

Thus we get

\gamma = 13.42 \cfrac{lb \cdot s}{ft}

The value of the damping coefficient when the system is critically damped is 13.42 lb s/ft.

4 0
3 years ago
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