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Paha777 [63]
3 years ago
9

Which pair of labels is correct? A: Maximum kinetic energy C: Maximum gravitational potential energy B: Maximum kinetic energy D

: Maximum gravitational potential energy A: Maximum gravitational potential energy C: Maximum kinetic energy B: Maximum gravitational potential energy D: Maximum kinetic energy
Physics
2 answers:
MAVERICK [17]3 years ago
5 0

Answer: C. A:Maximum gravitational potential energy C: Maximum kinetic energy

Explanation:

RUDIKE [14]3 years ago
4 0
Maximum kinetic enerygy
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What type of galaxy is M82 based on its appearance in the visible-light view?
SSSSS [86.1K]
<h2>Answer: irregular</h2>

According to Hubble  galaxies are classified into elliptical, spiral and irregular.

 

It should be noted this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.  

The classification is as follows:  

1. Elliptical galaxies: Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.  

2. Spiral galaxies: They have the shape of flattened disks containing some old stars and also a large population of young stars, enough gas and dust, and molecular clouds that are the birthplace of the stars.  

3. Irregular Galaxies:  Galaxies that do not have well-defined structure and symmetry.  

In this context, galaxy M82 does not match with the first two types of galaxies, because it has not a defined shape.

Therefore, M82 is an  irregular galaxy.

4 0
3 years ago
Circuit A in a house has a voltage of 208 V and is limited by a 40.0-A circuit breaker. Circuit B is at 120.0 V and has a 20.0-A
Setler79 [48]

Given Information:  

Voltage of circuit A = Va = 208 Volts

Current of circuit A = Ia = 40 Amps

Voltage of circuit B = Vb = 120 Volts

Current of circuit B = Ib = 20 Amps

Required Information:  

Ratio of power = Pa/Pb = ?

Answer:  

Ratio of power = Pa/Pb = 52/15

Explanation:  

Power can be calculated using Ohm's law

P = VI

Where V is the voltage and I is the current flowing in the circuit.

The power delivered by circuit A is

Pa = Va*Ia

Pa = 208*40

Pa = 8320 Watts

The power delivered by circuit B is

Pb = Vb*Ib

Pb = 120*20

Pb = 2400 Watts

Therefore, the ratio of the maximum power delivered by circuit A to that delivered by circuit B is

Pa/Pb = 8320/2400

Pa/Pb = 52/15

4 0
3 years ago
Which example possesses mechanical potential energy?. A. a taut guitar string. B. an oscillating pendulum. C. a roller coaster r
NeTakaya
<span>
The taut guitar string haspotencial energy which we can see in action.</span>  <span>· so option a is correct.</span>
7 0
3 years ago
Read 2 more answers
1.) an object moves along the x axis, subject to the potential energy shown. The object has a mass of 1.1kg and starts at rest a
MrRa [10]
If I'm not wrong #1 should be C
4 0
3 years ago
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ
pantera1 [17]

Answer:

The period is T =  0.700 \ s

Explanation:

From the question we are told that  

    The mass is m =  0.350  \ kg

     The extension of the spring is  x =  12.0 \ cm = 0.12 \ m

       

The spring constant for this is mathematically represented as

       k  = \frac{F}{x}

Where F is the force on the spring which is mathematically evaluated as

       F  =  mg  =  0.350 * 9.8

       F  =3.43 \ N

So  

    k  = \frac{3.43 }{ 0.12}

    k  = 28.583 \ N/m

The period of oscillation is mathematically evaluated as

      T =  2 \pi \sqrt{\frac{m}{k} }

substituting values

     T =  2  *  3.142*  \sqrt{\frac{0.35 }{28.583} }

     T =  0.700 \ s

   

7 0
3 years ago
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