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GREYUIT [131]
3 years ago
9

To be effective, an exercise program must be?

Physics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

A.

uniquely tailored to every person

ExtremeBDS [4]3 years ago
3 0

To be effective, an exercise program must have an aerobic form, portion for strength enhancement, and a stretching part. These three things are essential because they each target specific improvements in your body. For example, aerobics can help you maintain your body’s fitness or make it better. This usually targets your heart rate and ensures that you burn fat while doing so. Second is strength enhancement; this will make sure that your body becomes better – not just in a feeble state. Lastly is stretching, your muscles are like rubber bands. You cannot end or start your exercise program without stretching simply because they can damage your muscles as well. Aside from this, stretching can stop you from shocking your body into a physical activity, which may cause you to lose consciousness or have undue stress and fatigue. 

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Which of the following is a graph of the velocity of an object as it falls fromrest if drag is not ignored? Explain your choice
MariettaO [177]

The air drag is a force that depends on the speed of an object relative to the wind. Under certain conditions, it can be modeled as:

F=-bv

Where b is a constant.

As a falling object reaches a speed so that its weight is cancelled out by the air drag, the object will reach a maximum velocity.

In a speed vs time gaph, the speed would approach the maximum speed like an asymptote.

On the other hand, since the object falls from rest, the initial speed on the graph must be zero.

Taking these considerations into account, the correct graph for the movement of an object that falls from rest if air drag is not ignored, is option B.

7 0
1 year ago
A cylindrical rod of copper (E = 110 GPa, 16 × 106 psi) having a yield strength of 240 MPa (35,000 psi) is to be subjected to a
Fynjy0 [20]

Answer:

d= 7.32 mm

Explanation:

Given that

E= 110 GPa

σ = 240 MPa

P= 6640 N

L= 370 mm

ΔL = 0.53

Area A= πr²

We know that  elongation due to load given as

\Delta L=\dfrac{PL}{AE}

A=\dfrac{PL}{\Delta LE}

A=\dfrac{6640\times 370}{0.53\times 110\times 10^3}

A= 42.14 mm²

πr² = 42.14 mm²

r=3.66 mm

diameter ,d= 2r

d= 7.32 mm

4 0
3 years ago
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alukav5142 [94]

A. Conduct an exam. Thomas might have a drug dependence.

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8 0
3 years ago
A 5kg cart moving to the right with a velocity of 16 m/s collides with a concrete wall and
Kryger [21]

Explanation:

mass, m = 5kg

initial velocity, u = 16m/s

final velocuty, v = -22m/s

change in momentum, ∆p = ?

∆p = m (v-u)

5(-22-16)

5(38)

∆p = 190kgm/s

check the calculations!

8 0
3 years ago
What happens when sodium undergoes a chemical reaction with chlorine?
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They combine as atoms, and separate as ions. When sodium and chlorine atoms come together to form sodium chloride (NaCl), they transfer an electron. The sodium (Na) atom transfers one electron to the chlorine (Cl) atom, so that they both have full outer shells. ... When this happens, the atom is called a positive ion.
3 0
4 years ago
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