Answer:
25
Step-by-step explanation:
Compare the data and get the answer
63
.10d + .05n = 5.25
.10(21) + .05n = 5.25
2.1 + .05n = 5.25
.05n = 3.15
n = 3.15/.05
n = 63
The range of the given graph is [5, ∞).
Range.
Range refers the set of possible output values, and if we have the graph, then the set of all possible y values on the graph is defined as the range.
Given,
Here we have the graph.
Through the given graph we have to find the range of the line.
As per the definition of range, we have identified that the range take the value of y axis.
While we lookin into the given graph, we have identified that the starting point of the line is
=> (0, 5)
In this point 0 refers the x coordinate and 5 refers the y coordinate. So, the starting range is 5.
And the end of the line is not pointed.
So, we can consider that this line goes infinitely.
So, the range of the graph is [5, ∞).
To know more about Range here.
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The answer would be 40 days
We achieve this answer by dividing the distance of the trip, 30 miles, by the distance traveled per day, 3/4 miles.
Answer:
5/28
Step-by-step explanation:
1/1 represents the whole amount of tickets.
4/7 are sold on Thursday.
an additional 1/4 are did on Friday.
fraction of available tickets on Saturday are therefore
1/1 - 4/7 - 1/4 = 4/1 - 16/7 - 1/1 = 28/1 - 16/1 - 7/1 = 5/1
that means out of 28 equal parts of the total number of tickets 16+7 = 23 parts have been sold.
so, there are only 5 out of the total 28 parts available on Saturday, and the fraction of available tickets is therefore 5/28.
we could have also tried to bring both fractions to the same denominator, and found that this is 28.
and then
4/7 + 1/4 = 4/4 × 4/7 + 7/7 × 1/4 =
= 16/28 + 7/28 = 23/28
and the whole is 28/28.
so we have 28/27 - 23/28 = 5/28 left.
surprise, surprise, it is the same result ...