What is the equation of the line h Th ya has a y intercept of (0,-3) and passes through the point (-9,-9)
1 answer:
Answer:
The line equation is given as: 3 y = 2 x - 9
Step-by-step explanation:
Here, Y intercept is at point ( 0.-3)
So, at x = 0, y = -3
or, C = -3
Also, the point on the equation line is (x,y) = (-9,-9)
Now, by <u>SLOPE INTERCEPT FORM</u> of a line equation,we get:
y = m x + C : m = slope of line ......... (1)
So, substituting the values of C and (x,y) , we get:
-9 = m (-9) + (-3)
or, -9 + 3 = - 9 m
or, m = -6/-9 = 2/3
or, m = 2/3
Now, substitute the value of m back in to the line equation (1)
Hence, the line equation is given as: 3 y = 2 x - 9.
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The given equation is <em>y</em> = 2ˣ
The equation for the transformation is; <em>y</em> = A·2ˣ + k
The points on the graphs are;
(0, 1), (1, -1) and (2, -5)
Plugging the <em>x </em>and <em>y</em>-values to find the value <em>A</em> and <em>k</em> gives the following simultaneous equations;
When <em>x</em> = 0, <em>y</em> = 1, therefore;
1 = A·2⁰ + k = A + k
1 = A + k...(1)
When <em>x</em> = 1, <em>y</em> = -1, which gives;
-1 = A·2¹ + k
-1 = 2·A + k...(2)
Subtracting equation (1) from equation (2) gives;
-1 - 1 = 2·A - A + k - k
-2 = A
1 = A + k, therefore;
1 = -2 + k
k = 2 + 1 = 3
k = 3
Which gives;
y = -2·2ˣ + 3 = 3 - 2·2ˣ
Learn more about the solutions to simultaneous equations here:
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