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Sholpan [36]
4 years ago
10

When a turtle is lying on a sunny riverbank,how is it’s body temperature affected when it starts swimming in a cool river

Chemistry
1 answer:
geniusboy [140]4 years ago
4 0

Answer:

When a turtle is lying on a sunny riverbank, it’s body temperature rises and when it starts swimming in a cool river, it's body temperatures drop.

Explanation:

Cold-blooded animals, like turtles, do not have an internal feedback loop that regulates constant body temperature – as warm-blooded animals do. Their body temperatures fluctuate with that of the environment. This is why you see animals like lizards basking on rocks to raise their body temperatures. When it too hot, then they seek the shade under these rocks to lower their temperatures.

Learn More:

For more on warm-blooded vs cold-blooded animals check out;

brainly.com/question/11796999

brainly.com/question/11904373

brainly.com/question/9506185

brainly.com/question/14357623

#LearnWithBrainly

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Compare how fast the rate of CO2 increase is in the last few hundred years with the rate of increase (or decrease, for that matt
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The rate of CO2 increase is in the last few hundred years is 10 times more with the rate of increase (or decrease, for that matter) in the preceding 400,000 years.

There are many possible reasons for this cause , some primary factors are listed below:

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7 0
2 years ago
Can our bodies produce salt also is it possible to use our body oil to cook
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3 0
3 years ago
Compare the root mean square speeds of O2 and UF6 at 65 degree Celsius
gayaneshka [121]
<h3>Answer:</h3>

The root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

<h3>Solution and Explanation:</h3>
  • To find how fast molecules or particles of gases move at a particular temperature, the root  mean square speed is calculated.
  • Root mean square speed of a gas is calculated by using the formula;

       Root mean square=\sqrt{ \frac{3RT}{M}

       Where R is the molar gas constant, T is the temperature and M is the molar mass of gas in Kg.

<h3>Step 1: Root mean square speed from O₂</h3>

Molar mass of Oxygen is 32.0 g/mol or 0.032 kg/mol

Temperature = 65 degrees Celsius or 338 K

Molar gas constant = 8.3145 J/k.mol

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.032}

                                        = 513.289 m/s

<h3>Step 2: Root mean square speed of UF₆   </h3>

The molar mass of UF₆ is 352 g/mol or 0.352 kg/mol        

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.352}

                                                 = 154.762m/s

Therefore; the root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

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3 years ago
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