The rate of increase is found by differentiating with resepect to time. The product rule comes into play here.
A = LW
dA/dt ≈ (dL/dt)·W + L·(dW/dt)
... = (6 cm/s)·(5 cm) + (7 cm)·(3 cm/s)
... = 30 cm²/s + 21 cm²/s
... = 51 cm²/s . . . . rate of area increase
Considering the relationship between velocity, distance and time, it is found that the total distance traveled was of 380 miles.
<h3>What is the relationship between velocity, distance and time?</h3>
Velocity is <u>distance divided by time</u>, that is:
v = d/t.
For the first day, we have that:
v = 40, t = t + 2, d = d + 20, hence:
40 = (d + 20)/(t + 2)
For the second day, we have that:
v = 60
60 = d/t
d = 60t
Then, replacing in the first equation:
40 = (60t + 20)(t + 2)
60t + 20 = 40t + 80
20t = 60
t = 3.
Then the distances are given by:
- First day: d = 60t + 20 = 60 x 3 + 20 = 200 miles.
- Second day: d = 60t = 60 x 3 = 180 miles.
- Total: 200 miles + 180 miles = 380 miles.
More can be learned about the relationship between velocity, distance and time at brainly.com/question/28143163
#SPJ1
Answer:4
Step-by-step explanation:
50*7000=350000
Answer:
200
Step-by-step explanation:
123.875 i think is the answer
