1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ziro4ka [17]
3 years ago
14

Whitch constellation has the most stars

Chemistry
1 answer:
Ivan3 years ago
4 0
Centaurus because it also has ten of the most brightest stars
You might be interested in
Please help ASAP I’ll make you u as brainlister please 100 points pelaseee
inessss [21]

Answer:

(C) im pretty sure is the answer

Explanation:

6 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!
Westkost [7]

Hello!

I believe the answer is A) Anaphase.

I hope it helps!

3 0
3 years ago
Read 2 more answers
The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h
LenKa [72]

The average speed is calculated using the following formulaspeed = \sqrt{\frac{3kT}{m} }


Where

k = 1.381 X  10^{-23} J / K

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = \frac{32}{6.023 X 10^{23} }

mass of one molecule of oxygen will be = 5.31 X 10^{-23} g = 5.31 X 10^{-26} kg

putting values

average speed = \sqrt{\frac{3 X 1.381 X  10^{-23} X 298}{5.31 X 10^{-26} kg} }

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

4 0
3 years ago
Read 2 more answers
When 20.0 grams of an unknown compound are dissolved in 500. grams of benzene, the freezing point of the resulting solution is 3
Lelu [443]

Answer: 120g/mol

Explanation:

The first step we are to take is to calculate the freezing point depression of the solution.

ΔT(f) = freezing point of pure solvent - freezing point of solution

ΔT(f) = 5.48 - 3.77

ΔT(f) = 1.71°C

Next we are to calculate the molal concentration of the solution using freezing point depression

ΔT(f) = K(f) * m

m = ΔT(f)/K(f)

m = 1.71/5.12

m = 0.333 molal

Now, we calculate the molecular weight of the unknown...

m = 0.333 mol = 0.333 mol X per kg of benzene

moles of X = 0.333 mol of X per kg of benzene * 0.5kg of benzene

moles of X = 0.1665

molecular weight of X = 20g of X/0.1665

molecular weight of X = 120/mol

5 0
3 years ago
Which combination(s) of alkyl bromide and carbonyl compound can be used to prepare the following product by reaction of the Grig
Fiesta28 [93]

Answer:

D. only 2 and 3

Explanation:

The Grignard compound or reagent is a highly reactive compound formed from the reaction between an ether solvent containing magnesium and a haloalkane. This compound can also be used to create a C-C bond (carbon-carbon). Based on the properties and structure of a Grignard compound, the answer is option D.

7 0
3 years ago
Other questions:
  • This formula equation is unbalanced.
    12·1 answer
  • What is the force of a 10 kg. and its velocity is 2m/s
    5·1 answer
  • 0.102 g of an unknown(non electrolyte) compound is dissolved in enough water to make 100. mL of a solution and has an osmotic pr
    12·1 answer
  • while doing an experiment you got stuck and didn't know how to proceed what will you do to continue with the experiment​
    15·1 answer
  • What are the 10 metals?​
    6·1 answer
  • What is the oxidation state of CI in CIO-<br><br> -1<br> +2<br> +1<br> 0
    13·1 answer
  • Which of the following is an example of radiation?( need explanations)
    14·1 answer
  • POS MOLECULES SPEED UP WHEN ENERGY IS CREATED AND SLOW DOWN WHEN ENERGY IS DESTROYED True False? explain why​
    7·1 answer
  • If the molecule could move upward without colliding with other molecules, then how high would it go before coming to rest? Give
    8·1 answer
  • A current is applied to two electrolytic cells in series. In the first, silver is deposited; in the second, a zinc electrode is
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!