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icang [17]
2 years ago
13

Benzene and toluene form ideal solutions. Consider a solution of benzene and toluene prepared at 25∘C. As suming that the mole f

ractions of benzene and toluene in the vapor phase are equal, calculate the composition of the solution. At 25∘C the vapor pressures of benzene and toluene are 95 and 28 torr, respectively.

Chemistry
2 answers:
Montano1993 [528]2 years ago
7 0

Answer:

XL(toluene) = 0.77

XL(benzene) = 0.23

Explanation: see attachment

Pie2 years ago
5 0

Answer:

Xtoluene = 0.77

Xbenzene = 0.23

Explanation:

Step 1: Data given

Temperature = 25.0 °C

the mole fractions of benzene and toluene in the vapor phase are equal

At 25∘C the vapor pressures of benzene and toluene are 95 and 28 torr.

Step 2:

Xtoluene + Xbenzne = 1

Since the mol fractions are equal, the partial pressure also will be equal.

pToluene = pbenzene

Xtoluene *pToluene = Xbenzene *pBenzene = (1.00 - Xtoluene)*pBenzene

⇒with X toluene = mol fraction of toluene

⇒pbenzene = vapor pressure benzene = 95 torr

⇒Xbenzene = mol fraction benzene = 1.0 -0.5

⇒ptoluene = 28 torr

Xtoluene * 28 torr = (1.0 - Xtoluene)*95 torr

Xtoluene = 0.77

Xbenzene = 1.0 - 0.77 = 0.23

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A 25-liter sample of steam at 100°c and 1.0 atm is cooled to 25°c and expanded until the pressure is 19.71 mmhg. if no water con
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I will use [pV/T] in the state 1 = [pV/T] in the state 2.

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<h3>Answer:</h3>

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<h3>Solution:</h3>

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