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1 answer:
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Explanation:
First, we will calculate the entropies as follow.
J/K mol
As, = 298 K,
= 373.8 K
Putting the given values into the above formula we get,
J/K mol
=
= 18.5 J/K mol
Now,
=
= 94.2 J/mol K
Also,
=
= 33.4 J/K mol
Now, we will calculate the entropy of one mole of methanol vapor at 800 K as follows.
= (126.8 + 18.5 + 94.2 + 33.4) J/K mol
= 272.9 J/K mol
Thus, we can conclude that the entropy of one mole of methanol vapor at 800 K is 272.9 J/K mol.