The answer is force.
Hope this helps.
In exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.
Since the molecular formula of Hg₂(NO₃)₂ shows that for every mole of the substance, we have 2 moles of Hg, 2 moles of N and 6 moles of O.
So, in exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.
Learn more about number of moles here:
brainly.com/question/3935424
Answer:
Conduct more trials
Explanation:
Theoretical Probability can be defined as what someone is expecting to happen
Experimental Probability on the other hand, is defined as what actually happens.
Probability is usually calculated in the same way for experimental probability and that of theoretical probability. You divide the total number of possible ways in which a particular outcome can happen, by the total number of outcomes itself.
In Experimental probability, the more times a probability is tried, it gets closer and even more closer to theoretical probability.
So, for the question, Jamie should improve the number of tries more, so as to get his experimental probability results to be closer to the theoretical probability result.
Answer:
Final volume is 3.50L
Explanation:
It is possible to find volume of a gas using combined gas law:
<em>Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state</em>
If initial state of the gas is:
1.75L of a gas is at 700K and is under 250kPa of pressure
And final state is:
298K and 53.2kPa.
Replacing:
0.625L = 0.1785*V₂
<em>3.50L = V₂</em>
Thus, <em>final volume is 3.50L</em>
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
