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3 years ago

What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?

Chemistry

1 answer:

Valentin [98]3 years ago

3 0

Answer:

Explanation:

The pH of a solution can be found by using the formula

$pH = - log [ { H_3O}^{+}]$

From the question we have

$ph = - log(5.67 \times {10}^{ - 4} ) \\ = 3.2464$

We have the final answer as

Hope this helps you

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Is powder considered a liquid or a Solid?

Llana [10]

Answer:

Solid

Explanation:

Is this a trick question?

If not, solid.

7 0

2 years ago

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How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas

padilas [110]

Volume of NaOH required to react = 145.5 ml

<h3>Further explanation</h3>

Reaction

CO₂(g) + 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

$\tt mol~CO_2=\dfrac{0.45}{22.4}=0.02$

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

$\tt mol~NaOH=\dfrac{2}{1}\times 0.02=0.04$

Then volume of NaOH :

$\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.04}{0.275}\\\\V=0.1455~L\rightarrow 145.5~mL$

5 0

3 years ago

For H 3 PO 4 and H 3 BO 3 , does the subscript " of hydrogen in these two formulas seem to result in additional ions in solution

Kay [80]

Answer:

See Explanation

Explanation:

Let us consider the ionization of these compounds;

H3PO4 ⇔3H^+ + PO4^3-

H3BO3 ⇔3H^+ + BO3^3-

The next to consider is the type of electrolyte the both solution are; the both solutions are weak electrolytes and weak electrolytes do not ionize to a large extent.

The implication of this is that, not so much number of ions is added to the solution due to the poor ionization of these weak electrolytes. Hence, in spite of the subscript of 3, the conductivity of the solution does not significantly improve for the reason stated here quite unlike when strong electrolytes are used.

6 0

3 years ago

Tell how you could distinguish between the pair of compounds by their infrared spectra: compound a ch3ch2ch2n(ch3)2 and compound

maksim [4K]

Answer:-

b. compound b will show an nh absorption while compound a will not.

Explanation:-

For compound B CH3CH2CH2NH2 there are two N-H bonds present. So it will show NH absorption.

But in compound A CH3CH2CH2N(CH3)2 there are no N-H bonds. So it will not show NH absorption.

6 0

4 years ago

PLSS HELP ASAP PLSS

Zepler [3.9K]

molar concentration of Na⁺ ions = 3 M

molar concentration of CO₃⁻ ions = 1.5 M

First the water will solvate the sodium carbonate (Na₂CO₃).

Second the 80 mL of water added will dilute the first solution.

Explanation:

When you dissolve the Na₂CO₃ in water, the following solvation process takes place:

Na₂CO₃ (s) + H₂O (l) → 2 Na⁺ (aq) + CO₃⁻ (aq)

To find the final concentration of Na₂CO₃ solution we use the following formula:

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (2) = concentration (1) × volume (1) / volume (2)

concentration of Na₂CO₃ solution = 2.5 M × 120 mL / 200 mL

concentration of Na₂CO₃ solution = 1.5 M

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume (L)

number of moles of Na₂CO₃ = 1.5 M × 0.2 L = 0.3 moles

Knowing the solvation process we devise the following reasoning:

if 1 mole of Na₂CO₃ produces 2 moles of Na⁺ ions and 1 mole of CO₃⁻ ions

then 0.3 moles of Na₂CO₃ produces X moles of Na⁺ ions and Y mole of CO₃⁻ ions

X = (0.3 × 2) / 1 = 0.6 moles of Na⁺ ions

Y = (0.3 × 1) / 1 = 0.3 moles of CO₃⁻ ions

molar concentration = number of moles / volume (L)

molar concentration of Na⁺ ions = 0.6 / 0.2 = 3 M

molar concentration of CO₃⁻ ions = 0.3 / 0.2 = 1.5 M

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molar concentration

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6 0

3 years ago