Sodium bicarbonate (or baking soda) will cause both exothermic and endothermic reactions when added to water. It becomes either unstable or stable carbonic acid, which will eventually become CO2. The reaction would be exothermic is when H2CO3 (Carbonic Acid unstable) is formed and endothermic is when CO2 is.
he mass defect of the helium nucleus ⁴He₂ is 0.030377 u
Further explanation
Mass defect means the difference between the mass of particles forming an atom with an atomic mass.
Δm = mass defect ( u )
mp = mass of proton ( u )
me = mass of electron ( u )
mn = mass of neutron ( u )
M = atomic mass ( u )
A = mass number
Z = atomic number
Let us now tackle the problem !
Given :
Unknown :
Δm = ?
Solution :
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Answer details
Grade: College
Subject: Physics
Chapter: Nuclear Physics
Keywords: Mass , Defect , Nucleon , Number , Atomic , Proton , Electron , Neutron
Answer:
The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.
In this case:
- c= 4.184

- m= 32 g
- ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C
Replacing:
Q= 32 g* 4.184
*14 °C
Solving:
Q= 1,874.432 J
<u><em>The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J</em></u>
Answer:=1
Explanation:H = 1, O = 16, C = 12, N = 14 and 14--13 = 1 and your answer is 1
Its an ore of uraninte i think.