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tatiyna
3 years ago
6

Consider a cloudless day on which the sun shines down across the United States. If 2014 kJ of energy reaches a square meter( m 2

) of the United States in one hour, how much total solar energy reaches the entire United States per hour? The entire area of the United States is 9,158,960 km 2 .
Chemistry
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

      \large\boxed{\large\boxed{18,450kJ/hour}}

Explanation:

1) <em><u>Radiation</u></em><u>'s ratio</u>: 2014 kJ/m²

2) <em><u>United States'</u></em><u> area</u>:  is 9,158,960 km² .

3) <u>Formula:</u>

  • Energy = ratio × area

4) <u>Conversion factor</u>:

         (1km)^2=(1,000m)2\\\\1km^2=1,000,000m^2\\\\1=1km^2/1,000,000m^2

5) <u>Solve</u>:

In one hour:

             E=2,014kJ/m^2\times 9,158,960km^2\times  1km^2/1,000,000m^2\\\\E=18,446kJ\approx 18,450kJ

That is per hour.

The answer is rounded to 4 signficant figures.

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The rate of a certain reaction is given by the following rate law: rate Use this information to answer the question below. At a
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Answer:

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

Explanation:

N_2+3H_2\rightarrow 2NH_3

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Initial rate of the reaction = R = 4.0\times 10^5 M/s

R = k\times [N_2][H_2]^3

4.0\times 10^5 M/s=k\times [N_2][H_2]^3

The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

[H_2]'=2[H_2]

R'=k\times [N_2][H_2]'^3=k\times [N_2][2H_2]^3

R'=8\times k\times [N_2][H_2]^3

R'=8\times R=8\times 4\times 10^5 M/s=3.2\times 10^6 M/s

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

7 0
4 years ago
What is the average speed of the car after 3 seconds
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Answer:

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Explanation:

8 0
4 years ago
What does each component of the punnet square represent
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3 0
3 years ago
When magnesium (mg) metal is placed in hydrochloric acid (hcl), it forms magnesium chloride (mgcl2) and a gas. what gas is forme
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6 0
3 years ago
Read 2 more answers
The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2
Artyom0805 [142]
Answer:
1.7 * 10^-5

Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles

2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq) 
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5

Hope this helps :)
7 0
4 years ago
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