4 years ago

How do I solve for this?

Mathematics

1 answer:

Alenkasestr [34]4 years ago

8 0

Answer: whats your question?

Step-by-step explanation:

You might be interested in

Write an equation in the form of y=mx + b that represents a linear relationship with a slope of 2 and a y-intercept of 7.

podryga [215]

Answer:

y = 2x + 7

The m in the equation is the slope and the b is always the y-intercept.

5 0

3 years ago

If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1) FIRST BEST ANSWER BRAINLIEST

AURORKA [14]

Answer: See below

Step-by-step explanation:

$h\:\circ \:g=h\left(g\left(x\right)\right)$

$=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)$

$=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)$

$=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36$

Simplify:

$=245x^4-280x^3-214x^2+168x+81$

6 0

3 years ago

Write the letter below for each fraction in the correct box?

xxTIMURxx [149]

In order from left to right:
D, C, A, B

7 0

3 years ago

Read 2 more answers

Solve the equation to find a positive value of c: 62 + 82 = c2

Artist 52 [7]

$c^{2}$ = 144
c = ± $\sqrt{144}$
c = ±12

5 0

4 years ago

Read 2 more answers

Please help

Ipatiy [6.2K]

Answer:

cos (theta) = √21/5

Step-by-step explanation:

sin (theta) = 2/5

(sin (theta))^2 = 4/25

4/25 + (cos (theta))^2 = 1

(cos (theta))^2 = 1 - 4/25 = 21/25

cos (theta) = √21/5

4 0

3 years ago