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Brilliant_brown [7]
3 years ago
15

(-8a^2 - 1)(3a^2 - 5)

Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

13a² + 5

Step-by-step explanation:  

Not 100% but 90% sure. Work on Picture.

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The value of the solid's surface area is equal to the value of the solid's volume. Find the value of x. We know the length is 9
Lerok [7]

Given:

The value of the solid's surface area is equal to the value of the solid's volume.

Length(l) = 9 units

width(b) = 4 units

Height(h) = x units

To find:

The value of x.

Solution:

Solid's surface area is

Area=2(lb+bh+hl)

Area=2(9\times 4+4\times x+x\times 9)

Area=2(36+4x+9x)

Area=2(36+13x)

Area=72+26x

Volume of solid is

Volume=l\times b\times h

Volume=9\times 4\times x

Volume=36x

Solid's surface area = Volume of solid

72+26x=36x

72=36x-26x

72=10x

Divide both sides by 10.

7.2=x

Therefore, the value of x is 7.2.

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3 years ago
Which rule describes the composition of transformations that maps pre-image ABCD to final image A"B"C"D"? Reflection across the
svetlana [45]

Answer:

A on edge 2020

Step-by-step explanation:

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4 years ago
This Venn diagram represents the science subjects studied by students. What is the probability that a student, chosen at random,
kow [346]

Answer:

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3 years ago
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Graph the image of square CDEF after a reflection across the x-axis​
Rina8888 [55]

Answer:

If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:

(x,-y)

So we only change the sign of the y-component.

Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.

Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.

The original vertices are:

C = (-3, 7)

D = (0, 7)

E = (0, 10)

F = (-3, 10)

Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:

C' = (-3, -7)

D' = (0, -7)

E' = (0, - 10)

F' = (0, - 10)

Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.

5 0
3 years ago
−4x−2y x−2y ​ =−2 =9 ​
fenix001 [56]
Dy\dx=-2+y/x+1 is the answer I think
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3 years ago
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