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bonufazy [111]
3 years ago
5

Please help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!#5

Mathematics
1 answer:
Evgen [1.6K]3 years ago
5 0
A is the correct answer.
You might be interested in
Which value of x makes the equation -5x-(-7-4x) =-2(3x-4 true?
Ludmilka [50]

Answer:

x = 1/5

Step-by-step explanation:

Step 1: Write equation

-5x - (-7 - 4x) = -2(3x - 4)

Step 2: Solve for <em>x</em>

  1. <u>Distribute:</u> -5x + 7 + 4x = -6x + 8
  2. <u>Combine like terms:</u> -x + 7 = -6x + 8
  3. <u>Add 6x to both sides:</u> 5x + 7 = 8
  4. <u>Subtract 7 on both sides:</u> 5x = 1
  5. <u>Divide by 5 on both sides:</u> x = 1/5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

-5(1/5) - (-7 - 4(1/5)) = -2(3(1/5) - 4)

-1 - (-7 - 4/5) = -2(3/5 - 4)

-1 - (-39/5) = -2(-17/5)

-1 + 39/5 = 34/5

34/5 = 34/5

5 0
3 years ago
It’s not A I failed and I stuck at math can someone plz help me thxxx
12345 [234]

Answer:

b. 12,960ft

Step-by-step explanation:

half of 24 gives you 12 therefore the answer must start from 12.

8 0
3 years ago
Helloooo can someone help meeeeeeeee
Liono4ka [1.6K]

Answer:

Option B, (48x^{8}y^{5})

Step-by-step explanation:

<u>Step 1:  Simplify the exponent</u>

(12x^{2}y^{3})(2x^{3}y)^{2}

(12x^{2}y^{3})(2^{2}x^{3*2}y^{1*2})

(12x^{2}y^{3})(4x^{6}y^{2})

<u>Step 2:  Simply the expression</u>

(12x^{2}y^{3}*4x^{6}y^{2})

(48x^{2+6}y^{3+2})

(48x^{8}y^{5})

Answer: Option B, (48x^{8}y^{5})

8 0
2 years ago
????????????????????????????
never [62]
It would be 12.5 square miles I would appreciate the Brainliest
8 0
3 years ago
a racing car starts fron rest .if it gains an acceleration of 5m/second square in 10 second ,calculate the final velocity.​
hjlf

Answer:

<em>The</em><em> </em><em>final</em><em> </em><em>velocity</em><em> </em><em>would</em><em> </em><em>be</em><em> </em><em>5</em><em>0</em><em> </em><em>m</em><em>/</em><em>s</em><em>.</em>

<em>Its</em><em> </em><em>by</em><em> </em><em>formula</em><em>,</em><em> </em>

<em>a =  \frac{v - u}{t}</em>

<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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