Answer:
Add 7 to both sides
Step-by-step explanation:
You would need to add 7 to both sides to cancel out the 7 on the right side of the equation to get x one step closer to being by itself.
Then you would get 4x = -8.
Next divide by 4 on both sides to get x by itself so do the inverse operation of what 4 was doing to x.
x = -2
The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.
<h3>How to determine the vertex for each function is a minimum or a maximum? </h3>
Given:
and

The generalized equation of a parabola in the vertex form exists

Vertex of the function f(x) exists (1, 5).
Vertex of the function g(x) exists (-2, -3).
Now, if (a > 0) then the vertex of the function exists minimum, and if (a < 0) then the vertex of the function exists maximum.
The vertex of the function f(x) exists at a maximum and the vertex of the function g(x) exists at a minimum.
To learn more about the vertex of the function refer to:
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Answer:
day 0, day 120
Step-by-step explanation:
You want to find the value of x that makes both y-values be the same:
y = y
30x +10 = -x^2 +150x +10
x^2-120x = 0 . . . . subtract the right side of the equation
x(x -120) = 0 . . . . . factor
Values of x that make this true are x=0 and x=120.
The same number of each car was sold on day 0 and day 120.
Six now have a good day happy face bye-bye
(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
t^3-t^2-2t+t^2-t-2
t^3+-3t-2