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2 years ago

13

Find the range of the function f (x) = 2x - 1 with the given domain -1, 0, 1, 2

1 answer:

AnnyKZ [126]2 years ago

4 0

Answer:2x-1

Step-by-step explanation:

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How to do -7x-3x+2=8x-8

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<span><span>If you would like to solve the equation </span>- 7 * x - 3 * x + 2 = 8 * x - 8, you can calculate this using the following steps:<span>

- 7 * x - 3 * x + 2 = 8 * x - 8
- 7 * x - 3 * x - 8 * x = - 8 - 2
- 18 * x = - 10 /(-18)
x = 10 / 18
x = 5/9

<span>The correct result would be </span>5/9<span>.</span></span></span>

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2 years ago

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Step-by-step explanation:

If you were asking what is the 3/4 the area of circle with radius 4 I can answer this.

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3/4*16π= 12π, thus your answer.

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3 years ago

Please help me, I already answered the first 3

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Step-by-step explanation:

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3 years ago

What is 3 divided by 1/3?

Vlada [557]

Answer:

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3 years ago

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The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago