Answer:
Step-by-step explanation:
5
Evaluate.
1934917632
this is evaluation
53 1/10 is the mixed number
we are given
quadratic equation as

now, we can find b and c from

we can see that coefficient of x^2 is 1
so, we will have to make coefficient x^2 as 1
so, we divide both sides by 3



now, we can simplify it

now, we can compare it with

we get


so, we get order pair as
..............Answer
Answer:
Data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20}
Step-by-step explanation:
The question is:
Which data set has the greatest spread for the middle 50% of its data
We have given the data sets:
{18,13,22, 17, 21, 24}
{17,19,22,26,17,14}
{13,17,12,21, 18,20}
{18,21,16,22,24,15}
To find the greatest spread for the middle we need to find the IQR for all the data sets and check which one is highest.
So,
For the first set: 22-17 = 5
For the second: 22-17 = 5
For the third set = 20-13 = 7
For the fourth set = 22-16 = 6
Since data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20} ....