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Advocard [28]
3 years ago
15

Whats the surface area of this figure

Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

504

Step-by-step explanation:

The area of the base is 14 x 14 which is 196

The area of one triangle is 1/2 x base length x height which is:

1/2 x 14 x 11 = 77

So the area of one triangle is 77. The area of all the triangles is the same and there are 4 triangles.

So the surface area is

196 + 77 + 77 + 77 + 77 = 504

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An average of 20 apples were sold from Monday to Friday. After the sales on Saturday and Sunday, the average apples sold per day
avanturin [10]
131 apples were sold on Saturday and Sunday.

Work:
Monday - Friday : 5 days
20 x 5 = 100 apples

Monday - Sunday: 7 days
33 x 7 = 231 apples

231 - 100 = 131
6 0
3 years ago
Stans steak house has a server to cook ratio of 5 to 2.The total number of servers and cooks is 42. How many servers does Stans
aivan3 [116]

Answer: 30 servers

5+2 = 7

42/7 = 6 sets of employees

5*6 = 30 servers

Step-by-step explanation:

5+2 = 7

42/7 = 6 sets of employees

5*6 = 30 servers

3 0
3 years ago
I need to be walked through this please.
Aleksandr [31]
Https://us-static.z-dn.net/files/dd1/572d05be5373c1dc9c067ca6690a41a1.jpeg

3 0
3 years ago
What is 452 X 652 + 79
lidiya [134]
ANSWER: 294,783

452*652=294,704

294,704+79=294,783
5 0
3 years ago
Read 2 more answers
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
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