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valentinak56 [21]

3 years ago

6

Estimate each quotient to the nearest whole number. Then, find the actual quotient. EASY PLS HELP

1 answer:

barxatty [35]3 years ago

3 0

Answer:

28 and 15

Step-by-step explanation:

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Can someone help me with this?

Marianna [84]

Look at the rectangle. The bottom side measures 8 miles, so the top side also measures 8 miles.

Now look at the upper right triangle. For the angle of 32 deg, the top side of the triangle is the adjacent leg of the triangle. The air distance, marked x, is the hypotenuse of the triangle.

The trig ratio that relates the adjacent leg and the hypotenuse is the cosine.

$\cos \theta = \dfrac{adj}{hyp}$

$\cos 32^\circ = \dfrac{8~miles}{x}$

$x = \dfrac{8~miles}{\cos 32^\circ}$

$x = 9.4 ~miles$

6 0

3 years ago

A water tower is in a shape of a cone. the tower is 30 ft. tall and 20 ft in diameter. what is the approximate maximum volume of

Mamont248 [21]

I hope this helps you

7 0

4 years ago

Read 2 more answers

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

3 years ago

Solve each absolute value equation<br> 2=|x|-1

photoshop1234 [79]

Answer:

x = ±3

Step-by-step explanation:

2 = |x| - 1

Add 1 to both sides: |x| = 3

⇒ x = ±3

7 0

3 years ago

Read 2 more answers

If Valerie deposited 12,000 into an account threat earns 15% simple annual interest how much money will she have after 3 years

Ad libitum [116K]

Answer:

The amount which she will have into account after 3 years is 17,400 unit

Step-by-step explanation:

Given as :

The principal which is deposited into an account = 12,000 unit

The rate of interest simple annual = 15%

The Time period = 3 years

Let The amount which she have after 3 years = A unit

<u>From simple Interest method</u>

Simple Interest = $\frac{Principal\times Rate\times Time}{100}$

Or , Simple Interest = $\frac{12,000\times 15\times 3}{100}$

Or, Simple Interest = $\frac{540,000}{100}$

∴ Simple Interest = 5,400 unit

Now,

Amount = Principal + Simple Interest

Or, A = 12,000 unit + 5,400 unit

∴ A = 17,400 unit

Hence The amount which she will have into account after 3 years is 17,400 unit . Answer

6 0

3 years ago