9514 1404 393
Answer:
- 3n+6 (n = smallest)
- 3n (n = middle)
Step-by-step explanation:
The usual method for doing this is to let n represent the smallest one. Then the three integers are ...
n, n+2, and n+4
and their sum is ...
(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)
_____
Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:
(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)
The answer is in the picture
Really big numbers that can easily be estimated.
like
9,998 - 2,999
<u><em>Answer</em></u>
<u><em>Explanation</em></u>
Based on the given conditions, formulate:: 
Substitute into 
:: 
Rearrange variables to the left side of the equation: 
Calculate the sum or difference: 
Divide both sides of the equation by the coefficient of variable: 
Cross out the common factor:
