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creativ13 [48]
3 years ago
5

if you wanted to leave a 15% tip on your meal that cost $45.68 how much tip would you leave show your work please

Mathematics
1 answer:
Liula [17]3 years ago
4 0
First, you have to change the 15% into a decimal. The decimal would be 0.15
Next, you multiply the cost of the meal, 45.68, by 0.15
That makes 6.852, but since we're talking about money, just round it to 6.85
So 6.85 is the tax
You add the original price and the tax to get the total: 45.68 + 6.85 = 52.53
The total cost is 52.53

The answer is 6.85
I hope this helped!
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PLEASE HELP ME<br>Will mark brainliest ​
Vikki [24]

Answer: Its the last one trust me

Step-by-step explanation:

7 0
3 years ago
The sum of 45% of a number and 55% of the same number is 200. what is the number?
Ymorist [56]

.45x+.55x=200
Combine like terms
1x=200
So x is 100

Or you can do 45%+55%=100%
And 100% of 200 is 200
8 0
3 years ago
Please help me with my work I’ll give Brainlest
lbvjy [14]

Answer:

I believe it's a^2 * b^2 = c^2

Step-by-step explanation:

a^2 * 9^2 = 15^2

hope this helps! :)

6 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
Can someone please help me
DaniilM [7]

Answer:

with what

Step-by-step explanation:

tell me i think i can help

3 0
4 years ago
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