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olga_2 [115]
3 years ago
6

Write the following number in standard form.Two million, four thousand, twenty-six

Mathematics
2 answers:
nalin [4]3 years ago
5 0
200004026 hope it helped
Mashutka [201]3 years ago
3 0

Answer:

20,004,026 (Standard form = word notation)

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What is a story to represent the division problem 6 divided by 1/3??plz answer ASAP!!❤️
Gnom [1K]

Answer:

You have a jug holding 6 liters of water. Water from the jug is to be poured into small water bottles which can hold 1/3 liters of water each. How many bottles can you fill with this water?

Step-by-step explanation:

Total quantity of water available = 6 liters

Water that can be filled in each bottle = \frac{1}{3} liter

Since one bottle can hold \frac{1}{3} liter, in order to find how many bottles can hold 6 liters, we need to divided 6 by \frac{1}{3}.

So,

Total number of water bottles that can be filled are = \frac{6}{\frac{1}{3} }=6 \times 3 = 18

Therefore, we can fill 18 water bottles using the water from the jug.

6 0
3 years ago
3. The product of 7/10 and another factor
kicyunya [14]
The correct answer is d 7/7
4 0
4 years ago
A rectangular vegetable patch has a perimeter of 36 meters and an area of 80 square meters. What are the dimensions of the veget
hjlf

Answer: 5 and 4

Step-by-step explanation:

Perimeter = 2 ( L + W)

18 = 2(L + W) divide through by 2

9 = L + W

9 - L = W

Area = L * W

20 = L (9 - L)

20 = 9L - L^2

L^2 - 9L + 20 = 0 factor

(L - 5) (L - 4) = 0

Set both factors to 0 and solve for L

L = 5 and L = 4

5 0
3 years ago
Helpp !!! especially with 27 & 31
KengaRu [80]

Answer:

for number 31 it is 06,08 and 14 for 31 a

Step-by-step explanation:

5 0
4 years ago
Which of the following expression is equal to x^2+25?
nignag [31]
A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2


B: (x - 5i)^2
= (x  +   - 5i)(x +  - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2


C: (x - 5i)(x + 5i)
= (x +  - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2


D: (x + 10i)(x  - 15i)
= (x + 10i)(x +  - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
=  - 150i^2 + 5ix + x^2



Hope that helps!!!

6 0
3 years ago
Read 2 more answers
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